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3 years ago

If a triangular prism has a height of 9 a width of 9 and length of 6 what is the volume in cm3

Mathematics

1 answer:

zaharov [31]3 years ago

3 0

Volume = base area x height

Volume = 1/2 x 9 x 9 x 6 = 243 cm³

Answer: 243 cm³

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Ket [755]

Answer:C.

Step-by-step explanation:

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2 years ago

Stacey is selling tickets to the school play. the tickets are $7 for adults and $4 for children. she sells twice as many adult t

Alla [95]

Define x:

Let the number of children tickets be x.

Children tickets = x
Adult tickets = 2x

Construct the equation:
4x + 7(2x) = 108
4x + 14x = 109
18x = 108
x = 6

x = 6
2x = 12

Answer: 6 children tickets and 12 adult tickets.

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3 years ago

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A number minus 6 is less than or equal to 21

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3 years ago

Find the inverse of each function. g(n) = 2n+6/7

bulgar [2K]

Answer- 7n-6/2

Step by step explanation-

solution,

here

Given,

g(n)=2n+6/7

Let g(n) be y

So,

Interchanging the position of n and y we get the reverse So,

n = 2y+6/7

or, 7n = 2y+6

or, 7n-6 = 2y

or, 7n-6/2 = y

Therefore the inverse function of g(n) is 7n-6/2

Thank you.

6 0

3 years ago

f left parenthesis x right parenthesis equals StartFraction 16 x squared Over x Superscript 4 Baseline plus 64 EndFractionf(x)=1

Jlenok [28]

Answer:

a) Yes

b) (2,0.8)

c) $(2\sqrt2,1), (-2\sqrt2,1)$

d) $x \in (-\infty,\infty)$

e) (0,0)

f) (0,0)

Step-by-step explanation:

We are given the following function in the question:

$f(x) = \displaystyle\frac{16x^2}{x^4 + 64}$

a) We have to check whether given point lies on the function or not.

$(-2\sqrt2,1)\\\\f(-2\sqrt2) = \displaystyle\frac{16(-2\sqrt2)^2}{(-2\sqrt2)^4 + 64} = \frac{128}{128} = 1$

b) Find value of f(x) at x = 2

$f(2) = \displaystyle\frac{16(2)^2}{(2)^4 + 64} =\frac{64}{80}= 0.8$

Thus, (2,0.8) lies on the graph of given function.

c) We have to find the value of x, when f(x) = 1

$1 = \displaystyle\frac{16x^2}{x^4 + 64}\\\\x^4 -16x^2 + 64 = 0\\(x^2-8)^2 = 0\\x^2 - 8 = 0\\x = \pm 2\sqrt2$

$(2\sqrt2,1), (-2\sqrt2,1)$ lies on he graph of function.

d) Domain is the collection of all values of x for which the function is defined.

$x \in (-\infty,\infty)$

e) x-intercepts

This is the value of x such that the function is zero.

$0 = \displaystyle\frac{16x^2}{x^4 + 64}\\\\16x^2 = 0\\x = 0$

f) y-intercept

It is the value of function when x is zero.

$f(0) = \displaystyle\frac{16(0)^2}{(0)^4 + 64} = 0$

The function passes trough origin.

5 0

3 years ago