Let x=height. then base is x+4. plug what we know into the formula for the area of a triangle
A=½bh
16=½*(x+4)*(x)
32=x²+4x
x²+4x-32=0
(x+8)(x-4)=0
so x can be-8 our 4. when we plug-8 in for x we get a negative height. since a triangle cannot have a negative side length we discard-8 and try 4. height=4 and base=8
24x + 7=79
subtract 7 from both sides
24x + 7 - 7= 79 - 7
24x= 72
divide both sides by 24
x= 3
CHECK:
24x + 7= 79
24(3) + 7= 79
72 + 7= 79
79= 79
ANSWER: x= 3
Hope this helps! :)
-- The square of the shortest side . . . 16² = 256
-- The square of the medium side . . . 30² = 900
-- Their sum . . . (256 + 900) = <u>1,156</u>
-- The square of the longest side = 35² = <u>1,225</u>
1,156 and 1,225 are not equal, so these 3 numbers
<em>can</em> be the sides of a triangle, but it's not a right one.
The statement is <em>false</em>. (choice 'b')
Answer:
y - 7 = 16/13(x - 7)
General Formulas and Concepts:
<u>Alg I</u>
Point-Slope Form: y - y₁ = m(x - x₁)
Slope Formula: 
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-6, -9)
Point (7, 7)
<u>Step 2: Find slope </u><u><em>m</em></u>
- Substitute:

- Add:

<u>Step 3: Write equation</u>
y - 7 = 16/13(x - 7)
Answer:
57 deg
Step-by-step explanation:
Rhombus ABCD has diagonals AC and BD which intersect at point E.
The diagonals of a rhombus divide the rhombus into 4 congruent triangles.
If you find the measures of the angles of one of the triangles, then you know the measures of the angles of all 4 triangles.
Also, the diagonals of a rhombus are perpendicular.
Look at triangle BCE.
m<BCE = 33
m<BEC = 90
m<BCE + m<BEC + m<CBE = 180
33 + 90 + m<CBE = 180
m<CBE = 57
<ABE in triangle ABE corresponds to <CBE in triangle BCE.
m<ABE = m<CBE = 57
Answer: 57 deg