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Brut [27]
3 years ago
13

Calculate the value of k=xy

Mathematics
1 answer:
Masteriza [31]3 years ago
3 0

Answer:

Since k is constant, we can find k given any point by multiplying the x-coordinate by the y-coordinate. For example, if y varies inversely as x, and x = 5 when y = 2, then the constant of variation is k = xy = 5(2) = 10. Thus, the equation describing this inverse variation is xy = 10 or y = .planation:

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Hey:) can you please help me posted picture of question
juin [17]
Answer:
x² - 10x + 21

Explanation:
To answer this question, we will simply multiply each term from the first bracket by each term from the second and then combine like terms to get the final expression.

This can be done as follows:
(x - 3)(x - 7)
x(x) + x(-7) -3(x) -3(-7)
x² - 7x - 3x + 21
x² - 10x + 21

Hope this helps :)
4 0
3 years ago
Read 2 more answers
Assume that we have two events, and , that are mutually exclusive. Assume further that we know and . If an amount is zero, enter
sweet [91]

Answer:

Explained below.

Step-by-step explanation:

The complete question is:

Assume that we have two events, A and B, that are mutually exclusive. Assume further that we know P(A) = 0.30 and P(B) =0.40.

What is P(A and B)?

What is P(A | B)?

Is P(A | B) equal to P(A)?

Are events A and B dependent or independent?

A student in statistics argues that the concepts of mutually exclusive events and independent events are really the same, and that if events are mutually exclusive they must be independent. Is this statement accurate?

What general conclusion would you make about mutually exclusive and independent events given the results of this problem?

Solution:

The probability of the two events <em>A</em> and <em>B</em> are:

P(A) = 0.30 and P(B) =0.40

(a)

Compute the value of P (A ∩ B) as follows:

P(A\cap B)=0

This is because mutually exclusive events are those events that cannot occur together.

(b)

Compute the value of P (A | B) as follows:

P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{0.40}=0

Thus, the value of P (A | B) is 0.

(c)

No, P (A | B) is not equal to the P (A).

(d)

As mentioned in part (a), mutually exclusive events are those events which cannot occur together.

That is, P(A\cap B)=0.

Events A and B are independent  if the chance of their concurrent happening is equivalent to the multiplication of their distinct probabilities.

That is, P(A\cap B)=P(A)\times P(B).

The concepts of mutually exclusive events and independent events are not the same.

(e)

As the it is provided that A and B are mutually exclusive events, we know that P(A\cap B)=0.

Now compute the value of P(A)\times P(B) as follows:

               P(A)\times P(B)=0.30\times 0.40=0.12\neq 0

Thus, the events A and B are not independent.

Thus, if two events are mutually exclusive events they cannot be independent.

4 0
3 years ago
There are 5 students in class. each will be assigned a grade of a, b or
antiseptic1488 [7]
There could be five in each class.
8 0
3 years ago
Can sum help me?? will get brainlistt
raketka [301]

Answer:

C. Logan

Step-by-step explanation:

you divide the amount of problems by how many minutes it took each person. for example if you divide the amount of problems Logan did by how many minutes it took him. (84÷3) it equals 28.

7 0
2 years ago
1200$ invested at a rate of 3.5% compounded quarterly; 4 years
Tju [1.3M]

Step-by-step explanation:

<em>1st year</em>:

(1200 x 3.5 x 1) ÷ 100 = $42

<em>2nd year:</em>

(1242 x 3.5 x 1) ÷ 100= $43.47

<em>3rd year:</em>

(1285.47 x 3.5 x 1) ÷ 100= $44.99≈ $45

<em>4th year:</em>

(1330.47 x 3.5 x 1) ÷ 100= $46.56

Compound interest:

$(42 + 43.47 + 45 + 46.56)

=<u>$ 177.03</u>

4 0
3 years ago
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