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Marta_Voda [28]
3 years ago
10

Round 34 to the nearest 10

Mathematics
2 answers:
qaws [65]3 years ago
8 0

Answer:

30

Step-by-step explanation:


DaniilM [7]3 years ago
7 0

Answer:

<em>30</em>

Step-by-step explanation:

Keep the 3 as 3. Change the 4 to 0. You now have 30. Since 4 is less than 5, the 3 does not increase by 1 to 4, so the answer is 30.

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Solve the following inequality for w 8w+8&gt;-10w-5
Vlad [161]

Answer:

Step-by-step explanation:

8w+8 > -10w-5

18w + 8 > -5

18w > -13

w > -13/18

8 0
3 years ago
2. The height of one square pyramid is 24 m. A similar pyramid has a height of 8 m. The volume of the larger pyramid is 648 m3.
Dmitrij [34]
Larger PyramidHeight 24 Volume 648

Pyramid Volume = (Area of the Base * Height) ÷ 3648 = Base Area * 24 / 3Base Area = 648 * 3 / 24Base Area = 648 / 8Base Area = 81Base Length = 9
a) The Scale Factor between the Small & Large PyramidLength - 3LATERAL Area - 9Volume - 27

Slant Height^2 = 4.5^2 + 24^2Slant Height^2 = <span> <span> 596.25 </span> </span> <span><span>Slant Height^2 = 24.4182308941 </span> </span>
b)
Large Pyramid Area = (½ * Perimeter of Base * Slant Height) + Base AreaLarge Pyramid Area = (.5 * 36 * <span>24.4182308941) + 81
</span>Large Pyramid Area = 439.5281560938 + 81
Large Pyramid TOTAL Area = <span> <span> 520.5281560938 </span> </span> <span>Large Pyramid LATERAL Area =<span> 439.5281560938 </span> </span>


**********************************************************************************c)
Smaller PyramidHeight 8Surface Area = 124
This pyramid has dimensions that are one third of the larger pyramid.Therefore, it has a base length of 3.Base Area = 9.
Its base perimeter would be 12.
Small Pyramid Volume = (Area of the Base * Height) ÷ 3Small Pyramid Volume = ( 9 * 8 ) / 3Small Pyramid Volume = 72 / 3
c) Small Pyramid Volume =24 cubic meters

d) Ratio of larger pyramid volume to smaller pyramid volume648 / 24 = 27The reason? Volume is a 3 dimensional quantity.  The Larger pyramid is 3 times larger in terms of the base measurement.9 meters vs 3 meters - a factor of 3When we compare volumes, we have to cube this factor.3^3 = 27

Source : http://www.1728.org/volpyrmd.htm

3 0
3 years ago
For which function is f(x) equal to f^1(x) ( answer choices in picture )
Sonja [21]

Answer:

C. f(x)=\frac{x+1}{x-1}

Step-by-step explanation:

Let's find the inverse of each of the given options.

Option A:

f(x)=\frac{x+6}{x-6}\\y=\frac{x+6}{x-6}

To find f^{-1}(x), replace 'x' with 'y' and 'y' with 'x'. This gives,

x=\frac{y+6}{y-6}

Rewrite in terms of 'y'. This gives,

x(y-6)=y+6\\xy-6x=y+6\\xy-y=6x+6\\y=\frac{6x+6}{x-1}

The given function y=\frac{6x+6}{x-1}\ne y=\frac{x+6}{x-6}

So, option A is incorrect.

Option B:

f(x)=\frac{x+2}{x-2}\\y=\frac{x+2}{x-2}

To find f^{-1}(x), replace 'x' with 'y' and 'y' with 'x'. This gives,

x=\frac{y+2}{y-2}

Rewrite in terms of 'y'. This gives,

x(y-2)=y+2\\xy-2x=y+2\\xy-y=2x+2\\y=\frac{2x+2}{x-1}

The given function y=\frac{2x+2}{x-1}\ne y=\frac{x+2}{x-2}

So, option B is incorrect.

Option C:

f(x)=\frac{x+1}{x-1}\\y=\frac{x+1}{x-1}

To find f^{-1}(x), replace 'x' with 'y' and 'y' with 'x'. This gives,

x=\frac{y+1}{y-1}

Rewrite in terms of 'y'. This gives,

x(y-1)=y+1\\xy-x=y+1\\xy-y=x+1\\y=\frac{x+1}{x-1}

The given function y=\frac{x+1}{x-1}\ equals\ y=\frac{x+1}{x-1}

So, option C is correct.

Option D:

f(x)=\frac{x+5}{x-5}\\y=\frac{x+5}{x-5}

To find f^{-1}(x), replace 'x' with 'y' and 'y' with 'x'. This gives,

x=\frac{y+5}{y-5}

Rewrite in terms of 'y'. This gives,

x(y-5)=y+5\\xy-5x=y+5\\xy-y=5x+5\\y=\frac{5x+5}{x-1}

The given function y=\frac{5x+5}{x-1}\ne y=\frac{x+6}{x-6}

So, option D is incorrect.

Therefore, only option C is correct.

7 0
3 years ago
What is 1.8333 written as a simplified fraction
meriva
18333/10000
Convert to a fraction by placing the decimal number over a power of 10
5 0
3 years ago
Is the table linear or nonlinear?<br> X 0 1 2 3 <br> Y 2 4 8 16
RideAnS [48]

Answer:

It is linear

Step-by-step explanation:

The Y goes up by the same amount as the X (by 4 Y's per 1 X)

5 0
3 years ago
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