Answer:
1.44 mol
Explanation:
Given data:
Mass of Cu = 46 g
Moles of Ag produced = ?
Solution:
Chemical equation:
Cu + 2AgNO₃ → 2Ag + Cu(NO₃)₂
Number of moles of Cu:
Number of moles = mass/ molar mass
Number of moles = 46 g/63.546 g/mol
Number of moles = 0.72 mol
Now we will compare the moles of Cu and silver from balance chemical equation:
Cu : Ag
1 : 2
0.72 : 2×0.72 = 1.44 mol
Thus from 46 g of Cu 1.44 moles of Ag is produced .
D. you are not making any motion
Answer:
34 g/100 mL
Explanation:
The solubility of a compound can be expressed in g/100mL, for this we must divide the mass of the compound that dissolves in the solute by the volume of the solvent.
The solvent, in this case, is water, and that mass of the solute X that dissolved is the mass that was recovered after the solvent was drained and evaporated. So the solubility of X (S) is:
S = 0.17 kg/5L
S = 170g/5000mL
S = 170g/(5*1000)mL
S = 34 g/100 mL
Answer:
P2≈393.609Kpa so I think the answer is 394 kPa
Explanation:
PV=mRT Ideal Gas Law
m and R are constant because they dont change for the problem. That means
PV/T=mR = constant
so P1*V1/T1=P2*V2/T2 and note that the temperatures are in absolute temperatures (Kelvin) because you can't divide by zero.
So P2 = P1*V1*T2/(V2*T1) = 101325 Pa * 700 mL * 303K/(200 mL*273K)
P2 = 393609 Pa
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