What is the mass of oxygen in 25.0 grams of potassium permanganate , KMnO4?

Chemistry

2 answers:

MArishka [77]2 years ago

4 0

Answer: 10.1 g

I just did it and got i right

Katen [24]2 years ago

3 0

Answer:

10.76 grams

Explanation:

Given that the amount of $KMnO_4$ is 25.0 grams.

Mass of 1 mole of $KMnO_4$ = 158 grams

The number of atoms in 1 mole of $KMnO_4$ is 4.

Mass of oxygen in 1 mole of $KMnO_4$ = 16\times 4 = 68 grams.

Here, 158 grams of $KMnO_4$ has 68 grams of oxygen

So, the amount of oxygen in 1 gram of $KMnO_4$ = 68/158 grams

Therefore, the amount of oxygen in 1 gram of $KMnO_4$ = $\frac {68}{158}\times 25$ grams

=10.76 grams

Hence, 25 grams of $KMnO_4$ has 10.76 grams of oxygen.

You might be interested in

Which of the following is one way that land contributes to production?

Phantasy [73]

Answer : Option B) Energy from the environment fuels production.

Explanation : Environmental fuels can be produced from lands and contribute towards production. The land can contribute for the production of a Biogas plant and help in generating energy from the plant. It uses mainly decaying matter and household wastes which are decomposed and then produce methane gas is then connected to the household kitchens.

8 0

3 years ago

Read 2 more answers

A large flask is evacuated and weighed, filled with argon gas, and then reweighed. When reweighed, the flask is found to have ga

Elden [556K]

Answer:

100.52

Explanation:

from the ideal gas equation PV=nRT

for a given container filled with any ideal gas P and V remains constant.So T is also constant.R is as such a constant.

So n i.e no of moles will also be constant.

no of moles of Ar=3.224/40=0.0806