Answer:
If you add 10 more grams of Mg(OH)₂, the solution will shift the equilibrium to the ions production to consume the excessive Mg(OH)₂.
Explanation:
Mg(OH)₂(s) → Mg²⁺(aq) + 2OH⁻(aq)
K = 8.9 x 10⁻¹²
K = [Mg²⁺][OH⁻]²
The concentration of Mg(OH)₂ does not enter the equation because it is in the solid state.
[Mg²⁺] = x
[OH⁻]² = 2x
K = x.(2x)²
K = 4x³
4x³ = 8.9 x 10⁻¹²
x = 2.07 x 10⁻⁴ mol/L
At equilibrium:
[Mg²⁺] = x = 2.07 x 10⁻⁴ mol/L
[OH⁻]² = 2x = 4.14 x 10⁻⁴ mol/L
Explanation:
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Becoming an ionic electron
Electrons in sigma <span>bonds remain localized between two atoms. Sigma </span><span>bond results from the formation of </span><span>a molecular orbital </span><span>by the end to </span><span>end overlap of atomic </span>orbitals. Electrons<span> in pi</span> bonds can become delocalized between more than two atoms. Pi bonds result from the formation of molecular orbital by side to side overlap of atomic orbitals.
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