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3 years ago

A 1.0 kg ball is thrown into the air and initial velocity of 30 mi./s how high into the air did the ball travel

Chemistry

1 answer:

laila [671]3 years ago

6 0

Answer:

45.9m

Explanation:

Given parameters:

Mass of the ball = 1kg

Initial velocity = 30m/s

Unknown:

Height the ball will travel = ?

Solution:

At the maximum height, the final velocity of the ball will be 0;

Using ;

V² = U² - 2gh

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

h is the height

0² = 30² - (2 x 9.8 x h)

0 = 900 - 19.6h

h = 45.9m

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Answer:

The balanced chemical equation:

$C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)$

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Explanation:

$C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)$

Heat capacity of calorimeter = C = 11.66 kJ/°C

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Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

$\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol$

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