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andrew11 [14]
3 years ago
13

If a system has 2.00 × 10 2 kcal 2.00×102 kcal of work done to it, and releases 5.00 × 10 2 kJ 5.00×102 kJ of heat into its surr

oundings, what is the change in internal energy of the system?
Chemistry
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

336.8 kilo Joules is the change in internal energy of the system.

Explanation:

The equation for first law of thermodynamics follows:

\Delta U=Q+W

where,

Q = heat added to the system

ΔU = Change in internal energy

W = work done

We have :

Amount of heat given out by the system will be negatuive as heat relased by the system = Q

Q= -5.00\times 10^2 kJ

Work done on the system will positive as work is done on the system:

w = 2.00\times 10^2 kCal=836.8 kJ

\Delta U=-5.00\times 10^2 kJ+836.8 kJ=336.8 kJ

336.8 kilo Joules is the change in internal energy of the system.

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