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Paha777 [63]
3 years ago
5

Questions

Mathematics
1 answer:
Kisachek [45]3 years ago
7 0

Answer:2.3 0,8 40.3

Step-by-step explanation:

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there are quite a bit of them but i just need someone to convert these fractions to decimals....thanks<3
Mariana [72]

Answer:

1/9=0.111111111 2/9=0.222222222 3/9=0.333333333 4/9=0.444444444

5/9=0.555555556 6/9=0.666666667 7/9=0.777777778 8/9=0.888888889

Step-by-step explanation:

sorry i dont have time to do them all but heres all of the nines

4 0
3 years ago
Solve Y+3/5 = 1 1/10
lesya [120]

Answer:

y = 1/2

Step-by-step explanation:

Y+3/5 = 1 1/10

Subtract 3/5 from both sides.

y = 1/2

3 0
2 years ago
What is the height of a triangle that has an area of 63 yd and a base with a length of 18 yards
Greeley [361]

Answer:69

Step-by-step explanation:

Her

6 0
3 years ago
the side of a triangle are in the extended ratio of 3:2:4 if the length of the shortest side is 6cm what is the length of the lo
Nat2105 [25]
In the ratio, the numbers are 2 for the shortest side, 3 for the middle sized side, and 4 for the longest side.

2 is to 6 cm as 4 is to x

2/6 = 4/x

2x = 4 * 6

2x = 24

x = 12

Answer: The longest side measures 12 cm.
7 0
3 years ago
Suppose x=c1e−t+c2e3tx=c1e−t+c2e3t. Verify that x=c1e−t+c2e3tx=c1e−t+c2e3t is a solution to x′′−2x′−3x=0x′′−2x′−3x=0 by substitu
Harrizon [31]

The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

We differentiate

x = c1e^(-t) + c2e^(3t)

twice in succession, and substitute the values of x, x', and x'' into the differential equation

x''- 2x' - 3x = 0

and see if it is satisfied.

Let us do that.

x = c1e^(-t) + c2e^(3t)

x' = -c1e^(-t) + 3c2e^(3t)

x'' = c1e^(-t) + 9c2e^(3t)

Now,

x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]

= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)

= 0

Therefore, the differential equation is satisfied, and hence, x is a solution.

4 0
3 years ago
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