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Archy [21]
3 years ago
11

Please help! Late work!

Mathematics
1 answer:
frosja888 [35]3 years ago
3 0
(40+41+41+45+48+48+49+49+49+40)/10 = 460/10 = 46

mean = 46
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Natasha2012 [34]

Answer:

i cant see the picture

Step-by-step explanation:

5 0
4 years ago
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Find the length of the third side to the nearest tenth.<br> 8<br> 5
brilliants [131]

Answer:

The length of third side is: 6.3

Step-by-step explanation:

Given triangle is a right triangle where

Base = ?

Perpendicular = 5

Hypotenuse = 8

Let x be the base

As it is a right-angled triangle, Pythagoras theorem can be used to find the third side

Hypotenuse^2 = Base^2 + Perpendicular^2

Putting the known values

(8)^2 = x^2 + (5)^2\\x^2 = (8)^2-(5)^2\\x^2 = 64-25\\x^2 = 39\\

Taking square root on both sides

\sqrt{x^2} = \sqrt{39}\\x = 6.24499

Rounding off to the nearest 10th

Base = 6.3

Hence,

The length of third side is: 6.3

6 0
3 years ago
At Al's Athletic Club, the monthly membership fee for a student is $25 and the monthly
Igoryamba

Answer:

The relationship ⇒ <u>25x + 40y = 12,250</u>

Step-by-step explanation:

The number of student memberships = x

The number of adult memberships = y

The monthly membership fee for a student = $25

The monthly membership fee for an adult = $40

The total fee = 25x + 40y

Al's Athletic Club receives $12,250 in membership fees for the month of January.

So, the relationship between x and y is:

<u>25x + 40y = 12,250</u>

5 0
3 years ago
lagrange multiplier what are the points on the intersection of the ellipsoid with the plane that are respectively closest and fu
sleet_krkn [62]

The points on the intersection of the ellipsoid with the plane that are respectively closest and furthest from the origin are

(2–√,−2–√,2−22–√)

(−2–√,2–√,2+22–√)

Using Lagrange multipliers we attempt to find the extrema of f(x,y,z)=x2+y2+z2 given that g(x,y,z)=x−y+z−2=0 and that h(x,y,z)=x2+y2−4=0.

Given,

∇f=⟨2x,2y,2z⟩

∇g=⟨1,−1,1⟩

∇h=⟨2x,2y,0⟩

Extrema satisfy the condition that ∇f=μ∇g+λ∇h for some λ,μ∈R.

This is to say,

2x=2λx+μ

2y=2λy−μ

2z=μ

If λ=1 then μ=0 and so z=0, the g constraint tells us that x=y+2, and the h constraint tells us that y2+(y+2)2=4, meaning that either y=0 or y=2. This provides us with two crucial points in addition to the g constraint:

(2,0,0)

(0,−2,0)

Now assume λ≠1, and so

x=μ2−2λ

y=−μ2−2λ=−x

Since x=−y, we have that x=±2–√, y=∓2–√. Using the g constraint, our two critical points are

(2–√,−2–√,2−22–√)

(−2–√,2–√,2+22–√)

And then it's east to determine which is the max and which is the min out of these four critical points.

To learn more about Lagrange multiplier

brainly.com/question/4609414

#SPJ4

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2 years ago
Simplify: StartRoot StartFraction 27 x Superscript 12 Baseline Over 300 x Superscript 8 Baseline EndFraction EndRoot StartFracti
ale4655 [162]

The solution of the expression is \rm \dfrac{9\times x^4}{100}.

Given that

Equation; \dfrac{27x^{12}}{300x^8}

We have to simplify the equation.

According to the question

To simplify the equation follow all the steps given below.

Equation; \sqrt{\dfrac{27x^{12}}{300x^8}}

Then,

= {\dfrac{27x^{12}}{300x^8}}\\\\ = \dfrac{3\times 3\times 3 \times x^{8} \times x^{4}}{3 \times 100\times x^8}}\\\\=\dfrac{9\times x^4}{100}

Hence, the required expression is \rm \dfrac{9\times x^4}{100}.

To know more about Expression click the link given below.

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