Answer:
252 menu
Step-by-step explanation:
Total number courses, n = 10
The largest number of menu the chef can plan using his 10 main courses.
There are various combinations of menu obtainable from the available courses :
Ranging from :
nC0 to nCn
The largest number of menu he can plan is the highest output obtainable between :
10C0 to 10C10
10C0 = 1
10C1 = 10
10C2 = 45
10C3 = 120
10C4 = 210
10C5 = 252
10C6 = 210
10C7 = 120
10C8 = 45
10C9 = 10
10C10 = 1
Hence, the largest number of menu he can plan using his 10 main courses is 252
the top is adding 1 and the bottom is subtracting 5
The correct answer would be 128.
Answer:
56 and 43
Step-by-step explanation:
(x+13)+x = 99
2x+13 = 99
2x = 99-13
2x = 86
x = 86/2
x = 43
Smaller number = 43
Larger number is 56
Check
56-43 = 13
56+43 = 99