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enyata [817]
3 years ago
5

Another way to express the problem 1 - (-7)?

Mathematics
2 answers:
WARRIOR [948]3 years ago
6 0
1+7=8
Hope this helps :D
aliya0001 [1]3 years ago
4 0
One of the ways would be  1+7. Another is absolute value |1+ -(7)|. Or even |1+7| which is what the first absolute value would turn into since everything in it turns to positive.
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The cost of a company picnic varies directly as the number of employees attending the picnic. If a company picnic costs $487.50
Drupady [299]

The company picnic cost $ 1300 for 80 employees

<em><u>Solution:</u></em>

Given that cost of a company picnic varies directly as the number of employees attending the picnic

Let "c" be the company picnic cost

Let "n" be the number of employees attending the picnic

Therefore,

cost \propto \text{ number of employees attending picnic }

c \propto n\\\\c = kn

Where "k" is the constant of proportionality

c = kn ---------- eqn 1

<em><u>Given that company picnic costs $487.50 for 30 employees</u></em>

Therefore substitute c = 487.50 and n = 30

487.50 = k(30)\\\\k = \frac{487.50}{30} = 16.25

<em><u>How much does a company picnic cost for 80 employees?</u></em>

Substitute n = 80 and k = 16.25 in eqn 1

c = 16.25(80) = 1300

Thus $ 1300 is the cost for 80 employees

5 0
3 years ago
If the probabiliyt of nature 1 is 0.4 and the probability of nature 2 is 0.6, which alternative should be chosen?
Liono4ka [1.6K]
Should be chosen the bigger propability
0,6>0,4 
8 0
3 years ago
URGENT!! Really need help on this test
Katyanochek1 [597]

Answer:

G= L &M

H=L &M

K=P&N

J=P&N

7 0
3 years ago
The cost of renting a car is $42 a day plus 25 cents per mile. How far can Alex drive in one day if he only has $162
earnstyle [38]

Answer:

Alex can drive 480miles in one day period.

Step-by-step explanation:

$162- $42 =$120

$120/0.25¢=480

480miles

8 0
3 years ago
F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)
Butoxors [25]

Answer:

The function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

Explanation:

Given the functions;

\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}

Solving for the function;

(g\circ f)(x)=g(f(x))

so, we have;

\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}

Therefore, the function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

5 0
1 year ago
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