<u>To make this problem solvable, I have replaced the 't' in the second equation for a 'y'.</u>
Answer:
<em>x = -9</em>
<em>y = 2</em>
Step-by-step explanation:
<u>Solve the system:</u>
2x + 3y = -12 [1]
2x + y = -16 [2]
Subtracting [1] and [2]:
3y - y = -12 + 16
2y = 4
y = 4/2 = 2
From [1]:
2x + 3(2) = -12
2x + 6 = -12
2x = -18
x = -18/2 = -9
Solution:
x = -9
y = 2
Answer:
The student took 28 classes
Step-by-step explanation:
What I did was minus $15 from the $687 total, cause $15 is only a one time registration fee, then 687-15=672, so then I divided 672 by the cost per class, so $24, 672 divided by 24 equals to 28, so the student took 28 classes.
depression from the edge where she stands to the bottom of the opposite side is 52 degrees. How deep is the crevasse at this point? Round off to the nearest foot
sum = x(n+1)/2
where x is the number of the term ( in this case 52)
n is the last number in the series( which is not given in the problem)
Answer:
here you goes hope it helps you
Step-by-step explanation:
1
Common factor
−
3
2
+
7
+
2
0
-3y^{2}+7y+20
−3y2+7y+20
−
1
(
3
2
−
7
−
2
0
)
-1(3y^{2}-7y-20)
−1(3y2−7y−20)
2
Use the sum-product pattern
−
1
(
3
2
−
7
−
2
0
)
-1(3y^{2}{\color{#c92786}{-7y}}-20)
−1(3y2−7y−20)
−
1
(
3
2
+
5
−
1
2
−
2
0
)
-1(3y^{2}+{\color{#c92786}{5y}}{\color{#c92786}{-12y}}-20)
−1(3y2+5y−12y−20)
3
Common factor from the two pairs
−
1
(
3
2
+
5
−
1
2
−
2
0
)
-1(3y^{2}+5y-12y-20)
−1(3y2+5y−12y−20)
−
1
(
(
3
+
5
)
−
4
(
3
+
5
)
)
-1(y(3y+5)-4(3y+5))
−1(y(3y+5)−4(3y+5))
4
Rewrite in factored form
Solution
−
1
(
−
4
)
(
3
+
5
)
