Answer:
the operation we use to convert quarts to liters : multiply
Step-by-step explanation:
One quart is approximately equal to 0.95 liter
Here quart is the larger unit and liter is the smaller unit
To convert larger unit to smaller unit we multiply
given that 1 quart = 0.95 liter
2 quart = 2 times 0.95
3 quart = 3 times 0.05
so to convert quart of liter we multiply
the operation we use to convert quarts to liters we multiply by 0.95
Answer:
x = 9
Step-by-step explanation:
set a proportion: 8/12 = 6/x => 8x = 72 => x = 9
100 yd * 3ft/1 yd * 12 in /1ft
100*3*12 in
3600 in
10x-3(x-6)=-(x-1)
first distribute
10x -3x +18 = -x + 1
then you simplify
7 x +18 = -x +1
then you leave of when one side of x
6 x +18= +1
use opposite operation on the side with the x and do the same equation to the other side
6 x = -17
then divide
x = - 2.8333....
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
