Answer:
IQ scores of at least 130.81 are identified with the upper 2%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 100 and a standard deviation of 15.
This means that ![\mu = 100, \sigma = 15](https://tex.z-dn.net/?f=%5Cmu%20%3D%20100%2C%20%5Csigma%20%3D%2015)
What IQ score is identified with the upper 2%?
IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![2.054 = \frac{X - 100}{15}](https://tex.z-dn.net/?f=2.054%20%3D%20%5Cfrac%7BX%20-%20100%7D%7B15%7D)
![X - 100 = 15*2.054](https://tex.z-dn.net/?f=X%20-%20100%20%3D%2015%2A2.054)
![X = 130.81](https://tex.z-dn.net/?f=X%20%3D%20130.81)
IQ scores of at least 130.81 are identified with the upper 2%.
Answer:
Down below
Step-by-step explanation:
51+1 if you add them it equals
10 times 5 plus 2
104 divided by 2
Answer:
Step-by-step explanation:
3*2 * 4 * 9 =36 * 6 = 216
216 ( 4 < 7)
864 < 1512
3a) 3:1 or 3/1
3b) 3:4 or 3/4
4) 125 pages a day
5) 10 skittle per ounce in a bag
6) Market: $23.60/5= $4.72*7= $33.04, Orchard: $32.76/7= $4.68*5= $23.40, Which? Orchard because it is cheaper to buy 7 there than to buy 7 at market place because it is $00.30 cents cheaper at Orchard
7) Because money is always on top of time, amount, weight, etc.