Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
If the diameter of the cylinder's base is 10, then the radius is half that, or 5.
Answer:
fraction negative 4 over 5 is to the left of −0.4 and to the left of 0
Step-by-step explanation:
-4/5
-0.4 = -4/10 = -2/5
Answer:
13 19/40 more lbs
step-by-step explanation:
hope this helps
<span>A) 4x − 2y − z = −5
B) x − 3y + 2z = 3
C) 3x + y − 2z = −5
Looking at ALL 4 solutions, x =0 in all of them.
So, let's say x = 0, eliminate the "x's" and just keep equations B and C
</span>
<span>B) -3y + 2z = 3
C) y − 2z = −5
</span>Add B) and C)
-2 y = -2
y = 1
<span>1 − 2z = −5
</span>-2z = -6
z = 3
and x = 0
