3 years ago

A=14cm b=9cm c=6cm law of cosines

1 answer:

3 0

A^2= b^2+c^2 - 2bc•cosA

14^2= 9^2 + 6^2 -2x9x6xCosA
196= 81 + 36 - 108xCosA
196- 117= 108CosA
79/108= cos A
0.7315= cosA
A= cos^-1(0.7315)
A= 42.98

SineA/a=sineB/b= sineC/c

Sin42.98/14 = sineB/9
B = sin^-1((9•sin42.98)/14)
B= 25.99

C= 180-(25.99+ 42.98)
C= 111.03

You might be interested in

The volume of a cube is given by V = x3, where x is the length of an edge of the cube. The area of a square is given by A = x2,

ki77a [65]

X = 12 and A = 144 (If V = 1,728)

8 0

3 years ago

Answer this question please and thank you

Georgia [21]

0.377 + 5.51 = 5.887

Sorry I can only solve the first one. Could you give me a hint on how to do the second one ?

5 0

3 years ago

Read 2 more answers

7/7q+21= x /5q^2-45 then x=?

anzhelika [568]

Answer:

x = 5q - 15

Step-by-step explanation:

$\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15$