We have the following functions:
f (x) = 1 / (x-5)
g (x) = 7 / x
Multiplying the functions we have:
f · g = (1 / (x-5)) * (7 / x)
Rewriting:
f · g = (7 / x (x-5))
f · g = (7 / (x ^ 2-5x))
The domain of the function is:
All reals less:
x = 0
x = 5
Answer:
f · g = (7 / (x ^ 2-5x))
The domain of the function is:
All reals less:
x = 0
x = 5
Answer:
im not sure but i think its 151200
Step-by-step explanation:
12000 + %5 = 12600 x 12 = 151200 i could be completely wrong tho
Answer: The length of JF = 16 units.
Step-by-step explanation:
Given: In triangle DEF, segment DJ is a perpendicular bisector of side EF.
i.e. DJ is perpendicular to EF and DJ divides EF into two equal parts EJ and JF. [The perpendicular bisector is a line that is perpendicular to a line segment and splits it into two congruent segments.]
If EJ is 3y-8 and JF is 7y-40.
Then, 
![\Rightarrow\ 7y-3y=40-8\\\\\Rightarrow\ 4y=32\\\\\Rightarrow\ y=8 \text{ [Divide both sides by 4]}](https://tex.z-dn.net/?f=%5CRightarrow%5C%207y-3y%3D40-8%5C%5C%5C%5C%5CRightarrow%5C%204y%3D32%5C%5C%5C%5C%5CRightarrow%5C%20y%3D8%20%5Ctext%7B%20%5BDivide%20both%20sides%20by%204%5D%7D)
JF= 7(8)-40 =56-40= 16 units
Hence, the length of JF = 16 units.
Answer:
radius 4
center (3,6)
Step-by-step explanation:
(x - h)^2 + (y - k)^2 = r^2
coordinates of the center (h, k) and the radius is (r)
x² + y²- 6x - 12y +29=0
x² - 6x + y²- 12y +29=0
(x² - 6x) + (y²- 12y) +29=0
complete the square
(x² - 6x) + 9 + (y²- 12y) +36 +29= + 9 +36
(x² - 6x + 9) + (y²- 12y + 36) = + 9 +36 -29
(x-3)^2 + (y-6)^2 = 16
(x - h)^2 + (y - k)^2 = r^2
coordinates of the center (h, k) and the radius is (r)
center (3,6)
radius 4
cuemathcom
varsitytutors
Answer:
y= 2x -9
Step-by-step explanation:
<u>Slope-intercept </u><u>form</u>
y= mx +c, where m is the slope and c is the y-intercept.

Slope



= 2
Substitute m= 2 into the equation:
y= 2x +c
To find the value of c, substitute a pair of coordinates.
When x= 4, y= -1,
-1= 2(4) +c
-1= 8 +c
c= -1 -8
c= -9
Thus, the equation of the line is y= 2x -9.