Well, the person would be working 2 hours so twice as fast would be 4 hours. So I’m guessing it would take 8 hours
Answer:
For 3^-6 = 1/3^6 = 726 and for 3^-4 = 1/3^4 = 81
Step-by-step explanation:
ARE THE NUMBERS SEPARATED OR THEY ARE TO BE JOIN TOGETHER,IF THERE ARE SEPARATED THE SOLUTION IS GOING TO BE...
3^-6
using law of indices x^-a = 1/x^a
So 3^-6 = 1/3^6
Now find the power of 3^6
which is the same as 3×3×3×3×3×3 = 729
therefore 1/3^6 = 729
For 3^-4
using the above method
3^-4 is same as 1/3^4
which is equal to
finding the nominator
3×3×3×3 = 81
so the answer is 81
Answer:
A) (3,6)
Step-by-step explanation:
Let M be the midpoint of the line segment at (1,7) and (5,5). Then:

Answer:
So, the probability is P=0.0135.
Step-by-step explanation:
We know that at a certain airport, 65% of the flights arrive on time.
We get that p=0.65 and q=1-0.65=0.35.
We have 10 flights, so n=10.
We calculate the probability that all 10 of the flights were on time, so k=10.
We use the formulu:

we get:

So, the probability is P=0.0135.
F(x) = x+4
f(4) = 8, f(5) = 9
Change = 1
f(x) = 3x-7
f(-3) = -16, f(5) = 8
Change = 24/8 = 3
f(x) = 9x+1
f(-5) = -44, f(-2) = -17
Change = 27/3 = 9
f(x) = 2x+9
f(1) = 11, f(2) = 13
Change = 2
In order: f(x) = 9x+1, f(x) = 3x-7, f(x) = 2x+9, f(x) = x+4