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Aleksandr-060686 [28]
3 years ago
13

A sports magazine conducted a survey to find out the size of the viewership for three different sports in a state. The survey wa

s conducted in a basketball arena in the state. The magazine then published a circle graph on the viewership of basketball, baseball, and soccer in the state.
On the basis of this report, it was declared that basketball was the most viewed sport in the state. Is the report valid?
A.
Yes, because basketball is the most viewed sport in other states as well.
B.
Yes, because the data in the report was calculated accurately.
C.
No, because the survey was conducted in a basketball arena, and the people may have been biased in favor of basketball.
D.
No, because the mode of displaying the data is not appropriate.
Mathematics
2 answers:
Lina20 [59]3 years ago
7 0

Answer:

Your answer would be C. No, because the survey was conducted in a basketball arena, and the people may have been biased in favor of basketball.

Step-by-step explanation:

This is because they wanted to know which sport was viewed most so they would have needed to conduct a survey in like a public area outside of the areas of all the sports. By them doing a survey only in a basketball arena then they obviously were going to get a biased opinion of watching basketball, same as if a survey was done on a soccer or baseball field; in each area the people in that area would be biased toward the sport that is performed in that specific area. Hope this helped :)

  • {/} OfficialQue09 {\}
ratelena [41]3 years ago
3 0

Answer:

C

Step-by-step explanation:

This was a bias, because in the location, there must have been a greater concentration of basketball fans than fans of any other sport.

Hope this helped.

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<span>Therefore, the highest common factor of 12 and 15 is 3.</span>
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3 years ago
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you bought a mobile kit. you read the package that the weight of the entire mobile is 40 oz, each inch of crossbar weights 1 oz.
Nimfa-mama [501]

Answer:

See below

Step-by-step explanation:

<em>Refer to attache</em>d

Since 40 oz is total

<u>The weight of each shape indicated in the picture and calculated as:</u>

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As each inch weights 1 oz, there must be 5 of each shapes included in the kit

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3 years ago
PLEASE HELP I GIVE BRAINLIEST
bearhunter [10]
Slope-intercept form is:

\sf y=mx+b

Where 'm' is the slope and 'b' is the y-intercept.

Only the first equation is in slope-intercept form, so that crosses out the first and last options. It also crosses out the second option since the first equation is already in slope-intercept form.

For the third option, let's convert the second equation into slope-intercept and see for ourselves:

\sf 3y+x=-3

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<img src="https://tex.z-dn.net/?f=9%20%5Cfrac%7B9%7D%7B10%7D%20%20%2B%202%20%5Cfrac%7B1%7D%7B4%7D%20%20%3D%20%20%5C%5C%20%206%20
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Answer:

1. 445\frac{1}{2}

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3. 2\frac{11}{30}

Step-by-step explanation:

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I like to make it an improper fraction first.

\frac{99}{10}+\frac{9}{4}

Now take the LCM. The LCM is 20.

\frac{198}{20} +\frac{45}{20}

Now add them.

\frac{8910}{20}

Make this into a mixed number.

445\frac{1}{2}

That's your answer for number 1.

2. 6\frac{1}{4} -7\frac{1}{3}

Do the same thing as the previous addition problem but subtract instead.

\frac{25}{4} -\frac{22}{3}

\frac{75}{12} -\frac{88}{12}

-\frac{13}{12}=-1\frac{1}{12}

-1\frac{1}{12} is your answer for number 2.

3. 8\frac{2}{3}-6\frac{3}{10}

\frac{26}{3} -\frac{63}{10}

\frac{260}{30}-\frac{189}{30}

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2\frac{11}{30} is your answer for number 3.

I hope this helps! Let me know if you need help or if I got anything wrong :)

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<h3>What is the distance between points M and N?</h3>

From observation of the task content information; it can be deduced for a fact that the line segment MN which joins points M and N is parallel to the line JK. This follows from the fact that M and N are midpoints of KL and JL respectively.

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NM/19.6 = 7.4/(2×7.4)

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