Question

Joan needs a 0.053-M solution of HCl, but only has access to 2.12-M HCl, a 10-mL graduated pipet, and a 25-mL volumetric flask. How much HCl should she measure to create her desired solution

Answer 1

Answer:

Joan should measure 0.625 mL of 2,12 M HCl solution to create her desired solution.

Explanation:

Molarity of HCl Joan has access to = $M_1=2.12 M$

Volume of 2.12 M of HCl Joan use = $V_1=?$

Molarity of HCl Joan desired = $M_2=0.053 M$

Volume of 0.053 M of HCl Joan can prepare = $V_2=25 mL$

$M_1V_1=M_2V_2$

$V_1=\frac{M_2V_2}{M_1}$

$=\frac{0.053 M\times 25 mL}{2.12 M}=0.625 mL$

Joan should measure 0.625 mL of 2,12 M HCl solution to create her desired solution.