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vladimir1956 [14]
3 years ago
14

How many electrons will each ele-

Chemistry
1 answer:
Andre45 [30]3 years ago
6 0

<h2>Explanation:</h2><h3 /><h3>Oxygen- gains 2 electrons to form ions</h3><h3>Fluorine- gains 1 electron to form negative ions</h3><h3>Aluminum - loses three electrons to form ions</h3><h3>Calcium- loses 2 electrons in order to form ions</h3>

<h3>*Non metals gain electrons to form ions</h3><h3>*Metals loses electrons to form ions</h3>

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Butane gas reacts with oxygen gas to give carbon dioxide gas and water vapor (gas). If you mix butane and oxygen in the correct
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Answer:

118.776 mmHg

Explanation:

The equation of the reaction is;

C4H10(g) + 13/2 O2(g) ------> 4CO2(g) + 5H20(g)

Now the mole ratio  according to the balanced reaction equation is;

1 : 6.5 : 4 : 5

Hence, the total number of moles present = 1 + 6.5 + 4 + 5 = 16.5 moles

Mole fraction of water vapour = 5/16.5 = 0.303

We also know that;

Partial pressure= mole fraction * total pressure

Partial pressure of H20(g) = 0.303 *  392 mmHg = 118.776 mmHg

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3 years ago
A group of people take a diet pill. After 3 months, they measure the amount of weight they lost.
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dependent variable I think

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3 years ago
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Draw an alkyl bromide with proper stereochemistry that can be used to synthesize the given alkene as the exclusive product via a
enot [183]

Answer:

See explanation below

Explanation:

You forgot to put the picture to do so. In this case, I manage to find one, and I hope is the one you are looking for. If not, then post it again and I'll gladly help you out again.

According to the picture with the answer, we have a cyclohexane with 4 methyl groups there. Two of them are facing towards the molecule with a darker bond. This means that the alkyl bromide, should have a bromine in one of the bonds, and in order to produce an E2 reaction, this bromine should be facing in the opposite direction of the methyl groups which are facing towards. This is because an E2 reaction occurs with the less steric hindrance in the molecule. If the bromine is in the same direction as the methyl group, it will cause a lot more of work to do a reaction, and therefore, an E2 reaction. I will promote instead a E1 or a sustitution product.

Therefore the alkyl bromide should be like the one in the picture 2.

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Question 7
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