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aev [14]
3 years ago
11

How can a shoreline be destroyed by a Hurricane?

Chemistry
2 answers:
rodikova [14]3 years ago
4 0

Answer:

costal erosion

Explanation:

can cause erosion

EleoNora [17]3 years ago
4 0

Answer:

The water piles up with nowhere to go but onto land when it gets to the coast. The rising water, called storm surge, can submerge low-lying areas and towns along the coast. Combined with the crashing waves of the storm, the storm surge can cause demolishing docks, houses, roads, and erode beaches.

Explanation:

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Answer my my science homework please
ludmilkaskok [199]
1. D

2. <span>83.5 million years ago - 66 million years ago

3. </span><span>It had armor and could rotate to keep its caudal bludgeon facing the enemy.

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alisa202</span>
5 0
2 years ago
In which circumstance is displacement the same as distance traveled?
Ede4ka [16]
Distance travelled will be equal to displacement when the line drawn is completely straight. 

Hopefully, this helps.
8 0
2 years ago
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Which of the following elements would be the most reactive?
Aleksandr-060686 [28]
I think it's Chlorine but, not 100% sure. so C.
7 0
3 years ago
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How many moles of oxygen atoms are in 7.9E-1 moles of CO_2
Ilya [14]

Answer:

The number of moles of O atom in (7.9\times10^{-1}) mol of CO_{2} = 1.6

Explanation:

1 molecule of CO_{2} contains 2 atoms of O

So, (6.023\times 10^{23}) molecules of  CO_{2} contains (2\times6.023\times10^{23}) atoms of O.

We know that 1 mol of an atom/molecule/ion represents 6.023\times10^{23} numbers of atoms/molecules/ions respectively.

So, (6.023\times 10^{23}) molecules of  CO_{2} is equal to 1 mol of CO_{2}.

(2\times6.023\times10^{23}) atoms of O is equal to 2 moles of O atom.

Hence, 1 mol of CO_{2} contains 2 moles of O atom.

Therefore, (7.9\times10^{-1}) mol of CO_{2} contains (2\times7.9\times10^{-1}) moles of O atom or 1.6 moles of O atom.

3 0
2 years ago
A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the
Inessa05 [86]

Answer:

0.0613 L

Explanation:

Given data

  • Initial pressure (P₁): 1.00 atm
  • Initial volume (V₁): 1.84 L
  • Final pressure (P₂): 30.0 atm
  • Final volume (V₂): ?

Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 1.00 atm × 1.84 L / 30.0 atm

V₂ = 0.0613 L

6 0
3 years ago
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