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podryga [215]
3 years ago
5

PLEASE HELP!

Mathematics
2 answers:
Debora [2.8K]3 years ago
7 0

Answer:

B

Step-by-step explanation:

ratelena [41]3 years ago
5 0

Answer:

B

Step-by-step explanation:

B

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What is the product of 100 and 75
Genrish500 [490]

Answer:

In this question you have to find out the product. Product means simply multiplication. So multiplying 75×100 gives <u>7500</u> which is the correct answer.

pls give brainliest for the answer

6 0
3 years ago
Read 2 more answers
Determine the account balance of a simple interest account if the principal is $10,000, the interest rate is 1.5%, and the time
AnnZ [28]

Answer:

Capital: 2 400

Tasa: 5% = 5/100 = 1/20

Tiempo: 4 años

A) Interés = capital*tasa*tiempo

Interés = 2400*(1/20)*4

Interés = 480 soles

B) Interés = Capital*((1 + tasa)^tiempo+1)

Interés = 2400*((1 + 1/20)^4 + 1)

Interés = 2400*((21/20)^4 + 1)

Interés = 2400*(194 481/160 000 + 1)

Interés = 2400*(354 481/160 000)

Interés = 5 317,215Step-by-step explanation:

3 0
4 years ago
3(7 - 9k) + 23k = 4k -- (24 - k)
Novay_Z [31]

Answer:

k=5

Step-by-step explanation:

remove parenthese, combine like terms, move terms, combine like terms, divide both sides

6 0
4 years ago
It was found that the mean length of 100 diodes (LED) produced by a company
Lelechka [254]

Using the normal distribution, it is found that there is a 0.0228 = 2.28% probability that a diode selected at random would have a length less than 20.01mm.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem, we have that:

  • The mean is of \mu = 20.05.
  • The standard deviation is of \sigma = 0.02.

The probability that a diode selected at random would have a length less than 20.01mm is the <u>p-value of Z when X = 20.01</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{20.01 - 20.05}{0.02}

Z = -2

Z = -2 has a p-value of 0.0228.

0.0228 = 2.28% probability that a diode selected at random would have a length less than 20.01mm.

More can be learned about the normal distribution at brainly.com/question/24663213

3 0
2 years ago
Por Favor! Alguém me ajuda.
Nutka1998 [239]

Answer:

The answer is A.

Step-by-step explanation:

You have to apply :

{(a  -  b)}^{2} ⇒ {a}^{2}   -  2ab +  {b}^{2}

So for this question :

{(3a - b)}^{2}

=  {(3a)}^{2}  - 2(3a)(b) +  {(b)}^{2}

= 9 {a}^{2}  - 6ab +  {b}^{2}

8 0
4 years ago
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