Answer:
All of the above
Explanation:
An interrupt priority scheme is a system which decides the priority at which various work is done and it perform all of the above mention task so therefore all of the above is the right answer.
Answer:
Answered below
Explanation:
//Program is written in Java programming language
Class RegularPolygon{
int sides = 0;
int length = 0;
}
public void randomize(RegularPolygon polygon){
int randomSides = (int) 10 + (Math.random() * 20);
double randomLength = 5 + (Math.random() * 11);
polygon.sides = randomSides;
polygon.length = randomLength;
}
Answer:
def sum_digits(number):
total = 0
if 1 <= number <= 999:
while number > 0:
r = int (number % 10)
total +=r
number /= 10
else:
return -1
return total
print(sum_digits(658))
Explanation:
Write a function named sum_digits that takes one parameter, number
Check if the number is between 1 and 999. If it is, create a while loop that iterates until number is greater than 0. Get the last digit of the number using mudulo and add it to the total. Then, divide the number by 10 to move to the next digit. This process will continue until the number is equal to 0.
If the number is not in the given range, return -1, indicating invalid range.
Call the function and print the result
Answer:knowing how to build and program computers.
Explanation:
