Answer:
a)
#include <iostream>
using namespace std;
int main() {
bool a,b,c;
cin>>a>>b;
if(a^b)//X-OR operator in C++.
c=true;
else
c=false;
cout<<c;
return 0;
}
b)
#include <iostream>
using namespace std;
int main() {
bool a,b,c,d;
cin>>a>>b>>c;
if((a^b)^c)//X-OR operator in C++.
d=true;
else
d=false;
cout<<d;
return 0;
}
Explanation:
The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.
In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.
Answer:
gravitational force acting on that person.
Explanation:
in the Design section you can format your selected Chart
Packaged software is a compilation of programs which are grouped together in order to provide publicly with different tools in the same group.
Custom software is a specific program that are advanced for a goal in a department or in a company.
Answer: A. Multicast
Explanation:
Here we are given a situation where it is necessary for the device to stream media to all the PCs connected across the LAN. But as the they are unable to stream the media then it is a problem in the multicast TCP/Ip technology.
Multicasting enables to transfer information or messages from one to many or many to many. Here as a single device is responsible for streaming the content to other PCs across the LAN, therefore it is necessary that multicast has been properly implemented.
Option B is incorrect as it is not a scenario of broadcast as in broadcasting all the receivers must get the streaming however here if a PC does not want to receive the media stream it cannot receive for which multicasting is required.
Option C is incorrect as here we are not talking of one to one communication.
Option D is incorrect as here we cannot have more than one route to send the media content except the LAN.
