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3 years ago

Is there a frame of reference one can go into that seems to eliminate gravity as Newton described it?

Physics

1 answer:

andriy [413]3 years ago

3 0

Answer:

Yes such a frame exists: a free-fall (free-float frame) frame. This frame of reference is subject only to gravity and no forces such as electromagnetic forces or nuclear forces.

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Which statement accurately describes current electricity?

nikitadnepr [17]

Answer:

C???*

Explanation:

I forgot about this

4 0

3 years ago

Read 2 more answers

Two 100 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Bat -10 m/s when th

tatiyna

Answer:

b) -10 m/s

Explanation:

In perfectly elastic head on collisions of identical masses, the velocities are exchanged with one another.

3 0

3 years ago

A race car starting from rest accelerates uniformly at a rate of 4.90 meters per squared. What is the cars speed after it has tr

shusha [124]

Ok, we need to find a relation for the speed as it relates to the acceleration. This is given by the integral of acceleration:

$v= \int\limits^{t}_{0} {a} \, dt' =at$

Where we have the initial velocity is 0m/s and a will be 4.90m/s².

But we see there is an issue now... We know the velocity as a function of time, but we don't know how long the car has been accelerating! We need to calculate this time by now finding the position function as a function of time. This way we can solve for the time, t, that it takes to go 200m accelerating this way and then substitute that time into our velocity equation and get the velocity.
Position is just the integral of velocity:

$s= \int\limits^{}_{} {at} \, dt = \frac{1}{2}at^2$

Where the initial velocity and initial position are both zero.

Now we set this position function equal to 200m and find the time, t, it took to get there

$\frac{1}{2}(a \frac{m}{s^2} )t^2=200m \\ \\ \frac{1}{2}4.90 \frac{m}{s^2} t^2=200m \\ \\ t^2= \frac{400m}{4.90 \frac{m}{s^2}}=81.63s^2 \\ \\ t= \sqrt{81.63s^2 } =9.04s$

Now let's put t=9.04s into our velocity equation:

$v =at=4.9\frac{m}{s^2} \times 9.04s=44.3 \frac{m}{s}$

8 0

3 years ago

What is the best angle of projection for a projectile to reach the longest range?

Vedmedyk [2.9K]

Provided the projectile is landing at the same elevation as it is launched from, it is 45 degrees

8 1

3 years ago

if for every force there is an equal and opposite reaction force, how is it possible for an object to accelerate

lesya692 [45]

Answer:

By the use of the reaction force one body is able to accelerate because it is not fixed to a rigid support which offers a materialistic resistance.

Explanation:

For every force there is an equal and opposite reaction is stated in the Newton's third law of motion holds true universally.

This law accounts for the acceleration of the bodies with respect to the object that applies force on the other body. The acceleration is possible when iether one of the body is fixed and cannot move or when that both the bodies are not fixed can move.

For example consider a rocket with its engine started. This rocket generates upthrust by conversion of chemical energy of the fuel into the mechanical energy applying force on the launchpad. When this force is large enough it to lift the rocket then the rocket starts moving in the air and it accelerates. Now, when it is in the air or in vacuum during the course of its journey it uses the reaction of the burnt gases of the fuel to change the momentum.

This is in accordance with the Newton's second law of motion, stating that the Force is directly proportional to the rate of change in momentum.

8 0

3 years ago