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Zielflug [23.3K]
3 years ago
15

Physics Question: (ignore the part crossed in red) 14459688

Physics
1 answer:
adell [148]3 years ago
3 0
Spinning a marshmallow over a fire is effective maybe if you hang it over the fire and heat it up equally on each side
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¿Qué es la energía eólica?
Effectus [21]

Answer:

es la energia que se obtiene del vientoo,dicho de otro modo,es el aprovechamiento de la energia  cinetica de las masas de aire

Explanation:

4 0
4 years ago
A girl pulls her younger brother on a sled along a flat sidewalk (the total mass of the sled is 30kg). A frictional force of 50N
harkovskaia [24]

Answer:

6.13 s

219 N

Explanation:

Newton's law in the x direction:

∑F = ma

150 cos 30° N − 50 N = (30 kg) a

a = 2.66 m/s²

Δx = v₀ t + ½ at²

(50 m) = (0 m/s) t + ½ (2.66 m/s²) t²

t = 6.13 s

Newton's law in the y direction:

∑F = ma

Fn + 150 sin 30° N − (30 kg) (9.8 m/s²) = 0

Fn = 219 N

4 0
3 years ago
You jump off a platform 134 m above the Neuse River. After you have free-fallen for the first 40 m, the bungee cord attached to
omeli [17]

Answer:

The acceleration at lowest point is 19.62 m/s^2

Explanation:

Conservation of energy is an concept in which it is stated that the energy of an isolated object remains the same. Energy changes from one form to another.

Lets Assume

Constant of string is K

By using the conservation of energy we will have the following equation

1/2 x 80^2 x K = m x 9.81 x 120

3200 K =  1177.2 m

K = 1177.2 m / 3200

K = 0.368 m

At the lowest point we will have

a = ( K x X - m x g ) / m

a = ( 0.368 m x 80 - m x 9.81 ) / m

a = 19.62 m / s^2

So, the acceleration at lowest point is 19.62 m/s^2

7 0
3 years ago
Read 2 more answers
A wildlife researcher is tracking a flock of geese. The geese fly 4.0km due west, then turn toward the north by 40 degrees and f
BaLLatris [955]

Answer:

(a). The distance from the initial position is 6.68 km.

(b).  The magnitude of their displacement is 7.05 km.

Explanation:

Given that,

Geese fly 4.0 km due west, then turn to north by 40° and fly another 3.5 km.

(a). We need to calculate the distance from the initial position

Using formula of distance

D=AB+BC\cos\theta

Put the value into the formula

D=4.0+3.5\cos40

D=6.68\ km

(b). We need to calculate the magnitude of their displacement

Using formula of displacement

AC=\sqrt{CD^2+AD^2}

AC=\sqrt{(3.5\sin40)^2+(6.68)^2}

AC=7.05\ Km

Hence, (a). The distance from the initial position is 6.68 km.

(b).  The magnitude of their displacement is 7.05 km.

8 0
3 years ago
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ANSWER PLEASE FAST I NEED IT
Deffense [45]

14.0.5 cm 13. wind speed surface area temperature

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