Given parameters:
Mass of the car = 1000kg
Unknown:
Height = ?
To find the heights for the different amount potential energy given, we need to understand what potential energy is.
Potential energy is the energy at rest due to the position of a body.
It is mathematically expressed as:
P.E = mgh
m is the mass
g is the acceleration due to gravity = 9.8m/s²
h is the height of the car
Now the unknown is h, height and we make it the subject of the expression to make for easy calculation.
h = 
<u>For 2.0 x 10³ J;</u>
h = 
= 0.204m
<u>For 2.0 x 10⁵ J;</u>
h = 
= 20.4m
<u>For 1.0kJ = 1 x 10³J; </u>
h = 
= 0.102m
Answer:
b) 1.67×10^7 m/s
Explanation:
The solution is attached in the attachment section
Neither set of choices is correct.
If the distance is tripled, then the forces decrease to
1/9 Fg. and. 1/9 Fe.
Note. When the objects are charged, the gravitational force Fg can almost always be ignored, since Fe is like 10^40 greater when the quantities of mass and charge are similar.
Answer:
Change in momentum will be -4.4 kgm/sec
So option (A) is correct option
Explanation:
Mass of the ball is given m = 0.10 kg
Initial velocity of ball 
And velocity after rebound 
We have to find the change in momentum
So change in momentum is equal to 
( here negative sign shows only direction )
So option (A) will be correct answer
Answer:
14.49 g/cm²
Explanation:
I = Io e^-(ux)
Where:
I = 573
Io = 1045
x = 0.3 inches and
rho = 11.4g/cm^3
Using the conversion constant
1 inch = 2.54 cm;
0.3 inches = 0.3 * 2.54 cm
0.3 inches = 0.762 cm
I/Io = e^-(ux), or say
Io/I = e^(ux), taking the In of both sides
ln(Io/I) = ux, making u subject of formula
u = 1/x * ln(Io/I)
u = 1/0.762 * ln(1045/573)
u = 1.312 * 0.6
u = 0.787
Next, we say that
u/rho = 0.7872/11.4 = 0.069
And finally, we make
1/(u/rho) to be our final answer
Inverse of the answer is = 14.49 g/cm²
Therefore, the um^-1 in g/cm^2? is 14.49
