Answer:
see below
Step-by-step explanation:
What is the theoretical probability that the family has two dogs or two cats? (1/2)
The choices are dd, dc, cd, cc
There are 4 choices = dd or cc/ total = 2/4 = 1/2
Let the heads of the coin be dogs and the tails of a coin be cats
Flip two coins and coin A is the first pet and coin B is the second pet
heads , heads = 10
heads, tails 14
tails heads =13
tails tails = 13
total 50
Experimental probability 2 dogs or 2 cats = ( hh, tt) /total = ( 10+13) /50 = 23/50
If we had 3 pets
what is the theoretical probability that they have three dogs or three cats?
ddd, ddc, dcd, dcc, ccc, ccd ,cdc, cdd
There are 8 options
ddd or ccc/ total = 2/8 = 1/4
Let the heads of the coin be dogs and the tails of a coin be cats
Flip three coins and coin A is the first pet and coin B is the second pet Coin C be the third pet
four times.
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