The inequality is still true! If you add a number, say 5 to both sides of the following inequality, does anything change?
3 < 6
3 + 5 < 6 + 5
8 < 11
The inequality is still true. We know the statement holds for subtracting the same number because, in a way, addition and subtraction are pretty much the same operation. If I subtract 5 from both sides, I can think of it like "I add negative 5 to both sides" or something along those lines. It's kind of backwards thinking.
I think its 7 or 10 Dont remember that question
Answer:
9 cm, C
11 cm, B
14 cm A
Step-by-step explanation:
Answer:
Radius r=0.30m, Velocity, v=36m/s
(a) angular speed w=
r
v
=
0.3
36
=120rad/s
(b) final angular speed w
′
=0
From rotational kinematics w
′
2
−w
2
=2αθ
0−14400=2α×40×2π
⇒α=
160π
−14400
=−28.6rad/s
2
'Distance covered
=40×2πr
=40×2π×0.3=75.39m
Answer:
216 cookies
Step-by-step explanation:
From the question,
Let the total cookies in the first place be x cookies.
Their ratio = 5:12:9
Total = 5+12+9 = 26.
Weiming share = (5/26)x = 5x/26
If weiming sold 28 cookies
⇒ (5x/26)-28
⇒ (5x-728)/28
Hence Weiming new share = (5x-728)/28 cookies
The new ratio is 1:8:6
The total cookies becomes = x-28
Therefore,
(1/15)(x-28) = (5x-728)/28
(x-28)/15 = (5x-728)/28
Crossmultiply
28(x-28) = 15(5x-728)
28x-784 = 75x-10920
Collect like terms
28x-75x = -10920+784
-47x = -10136
x = -10136/-47
x = 215.7
x ≈ 216 cookies
