Find the value of x. x°+65°+109°+136°=310°
2 answers:
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Answer:
The values of x and y in the diagonals of the parallelogram are x=0 and y=5
Step-by-step explanation:
Given that ABCD is a parallelogram
And segment AC=4x+10
From the figure we have the diagonals AC=3x+y and BD=2x+y
By the property of parallelogram the diagonals are congruent
∴ we can equate the diagonals AC=BD
That is 3x+y=2x+y
3x+y-(2x+y)=2x+y-(2x+y)
3x+y-2x-y=2x+y-2x-y
x+0=0 ( by adding the like terms )
∴ x=0
Given that segment AC=4x+10
Substitute x=0 we have AC=4(0)+10
=0+10
=10
∴ AC=10
Now (3x+y)+(2x+y)=10
5x+2y=10
Substitute x=0, 5(0)+2y=10
2y=10
∴ y=5
∴ the values of x and y are x=0 and y=5
9514 1404 393
Answer:
y = 3/2x -10
Step-by-step explanation:
The point-slope equation can be written ...
y = m(x -h) +k . . . . . for a line with slope m through point (h, k)
Using the given values, this is ...
y = (3/2)(x -6) -1 = 3/2x -9 -1
y = 3/2x -10 . . . . . slope-intercept equation
