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Alexandra [31]
2 years ago
15

What is the slope of a line perpendicular to the line whose equation is 18x+3y=81 Fully simplify your answer.

Mathematics
2 answers:
S_A_V [24]2 years ago
7 0

Answer: m = \frac{1}{6}

Step-by-step explanation:

Find the slope of the line that is perpendicular to 18x + 3y = 81 :: m = 1/6

klasskru [66]2 years ago
3 0

Answer:

slope = \frac{1}{6}

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

18x + 3y = 81 ( subtract 18x from both sides )

3y = - 18x + 81 ( divide the terms by 3 )

y = - 6x + 27 ← in slope- intercept form

with slope m = - 6

given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-6} = \frac{1}{6}

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Which of the following rotations will produce a 12-sided polyhedron? ANSWERS: Rotating a 12-gon about a vertical axis running al
Komok [63]

Answer:

No rotation will produce a polyhedron. The solids of rotation are non-polyhedral.

Step-by-step explanation:

Solids of rotation will always have a curved face, so they’re always non-polyhedral.

5 0
3 years ago
Find the value of y when x equals 17 -x+y=-27
notka56 [123]
Find the value of y when x equals 17 -x+y=-27
since x is equal to 17 you plug it in the equation as follows...
-17+y=-27
then you add 17 on both sides...
y=-27+17
Answer:
y=-10
6 0
3 years ago
The sum of 2 times a number and 3 is 6
barxatty [35]
Is there a question or is this it ?
it basically answers itself because 2 times 3 is 6
6 0
3 years ago
Read 2 more answers
a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no
Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

<em><u>Solution:</u></em>

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

<em><u>Ten years ago he was twice as old as his son</u></em>

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

7 0
3 years ago
What is 2 2/5×2 7/9 in simplest mixed number form?
Scorpion4ik [409]

Answer:

6 2/3

Step-by-step explanation:

2 2/5 * 2 7/9

Change each number to an improper fraction

2 2/5 = (5*2+2)/5 = 12/5

2 7/9 = (9*2+7) = 25/9

12/5 * 25/9

Rewriting

25/5  * 12/9

5/1 * 4/3

20/3

Now changing to a mixed number

3 goes into 20 6 times with 2 left over

6 2/3

7 0
3 years ago
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