Answer:
Fossils, the shape of continents, the mid-ocean ridge system, sea floor sediment deposits, and the magnetism of rocks.
Explanation:
Fossils, the continent's shape, the mid-ocean ridge system, sea floor sediment deposits, and the magnetism of rocks on the sea floor are the evidences that support the theory of plate tectonics in the area. Fossils provides information to us when and where plants and animals once existed. Due to diverging plates, some life became isolated, and evolved into new species. Continental ‘fit’ through coastline matching. Some division of continents look as though they should fit together, e.g. South America and Africa.
Answer : % ionic character is 0.20%
Bonding between the two metals will be purely metallic.
Explanation: For the calculation of % ionic character, we use the formula
![\% \text{ ionic character}= [1-e^{\frac{-(X_A-X_B)^2)}{4}}]\times(100\%)](https://tex.z-dn.net/?f=%5C%25%20%5Ctext%7B%20ionic%20character%7D%3D%20%5B1-e%5E%7B%5Cfrac%7B-%28X_A-X_B%29%5E2%29%7D%7B4%7D%7D%5D%5Ctimes%28100%5C%25%29)
where 
& 
are the Pauling's electronegativities.
The table attached has the values of electronegativities, by taking the values of Al and Mn from there,
Putting the values in the electronegativity formula, we get
![\% \text{ ionic character}= [1-e^{\frac{-(1.61-1.55)^2)}{4}}]\times(100\%)](https://tex.z-dn.net/?f=%5C%25%20%5Ctext%7B%20ionic%20character%7D%3D%20%5B1-e%5E%7B%5Cfrac%7B-%281.61-1.55%29%5E2%29%7D%7B4%7D%7D%5D%5Ctimes%28100%5C%25%29)
= 0.20%
Now, there are 3 types of inter atomic bonding
1) Ionic Bonding: It refers to the chemical bond in which there is complete transfer of valence electrons between atoms
2) Covalent Bonding: It refers to the chemical bond involving the sharing of electron pairs between 2 atoms.
3) Metallic Bonding: It refers to the chemical bond in which there is an electrostatic force between the positively charged metal ions and delocalised electrons.
In 
compound, the % ionic character is minimal that is 
0.20% and there are two metal ions present, therefore this compound will have metallic bonding.
Potential because it hasnt released yet
Answer:
E) Two of the above statements are true.
Explanation:
The options are:
A) Before the solution is titrated with HCl it is pink and when the color changes from pink to colorless, the moles of H*(aq) equals the moles of OH"(aq) used in the hydrolysis of the neutralized aspirin. <em>TRUE. </em>Before the solution is titrated, there is an excess of NaOH (Basic solution, phenolphtalein is pink). Then, at equivalence point, after the addition of HCl, the pH is acidic and phenolphtalein is colorless.
B) Before the solution is titrated with HCl it is colorless and when the color changes from colorless to pink, the moles of H*(aq) equals the excess moles of OH(aq) added. <em>FALSE. </em>As was explained, before the titration, the solution is pink.
C) 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The titration with HCl allows us to determine the moles of excess OH(aq) added. Once we determine the moles of excess OH(aq), we can determine moles of OH"(aq) used in the hydrolysis of the neutralized aspirin, which is equal to the moles of aspirin in the recrystallized aspirin. <em>TRUE. </em>Aspirin requires an excess of base (NaOH) for a complete dissolution (Hydrolysis). Then, we add H+ as HCl to know the excess moles of OH-. As we know the added moles of OH-, we can find the moles of OH that reacted = Moles of aspirin.
D) We can determine the moles of aspirin in the recrystallized aspirin by titrating with the 0.100 M NaOH to the neutralization point. The purpose of the hydrolysis of the neutralized aspirin and the back-titration with the 0.100 M HCl is to confirm the moles of aspirin in the recrystallized aspirin. <em>FALSE. </em>NaOH can be added directly unyil neutralization point because, initially, aspirin can't be dissolved completely
E) Two of the above statements are true. <em>TRUE</em>
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Right option is:
<h3>E) Two of the above statements are true.</h3>
