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Alona [7]
3 years ago
7

Write the balanced chemical equation for the reaction between aqueous sodium carbonate and

Chemistry
1 answer:
ioda3 years ago
7 0

Answer:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

Explanation:

This question is asking to write and balance an equation between between aqueous sodium carbonate (Na2CO3) and aqueous nitric acid (HNO3). The equation is as follows:

HNO3 (aq) + Na2CO3 (aq) → NaNO3 (aq) + CO2 (g) + H2O (l)

However, this equation is not balanced as the number of atoms of each element must be the same on both sides of the equation. To balance the equation, one will make use of coefficients as follows:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

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During an experiment, the percent yield of calcium chloride from a reaction was 82.38%. Theoretically, the expected amount shoul
gregori [183]

Answer:

Actual yield = 86.5g

Explanation:

Percent yield = 82.38%

Theoretical yield = 105g

Actual yield = x

Equation of reaction,

CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O

Percentage yield = (actual yield / theoretical yield) * 100

82.38% = actual yield / theoretical yield

82.38 / 100 = x / 105

Cross multiply and make x the subject of formula

X = (105 * 82.38) / 100

X = 86.499g

X = 86.5g

Actual yield of CaCl₂ is 86.5g

7 0
3 years ago
How would you describe the behavior of particles in a solid?
ehidna [41]
A.

Particles within a solid only vibrate in place.
4 0
3 years ago
How many carbon atoms are present in a 10.0g sample of C3H8
balu736 [363]

Answer:

4.09ₓ10²³ atoms are contained in 10g of C₃H₈

Explanation:

1 mol of C₃H₈ has 3 mol of carbon and 8 mol of hydrogen.

1 mol of C₃H₈ weighs 44 g

In 44 g of C₃H₈ we have 3 mol of C

In 10 g of C₃H₈ we'll have (10 . 3)/ 44 = 0.681 mol

1 mol of C has NA (6.02x10²³) particles

0.681 mol will have (0.681 . 6.02x10²³) = 4.09ₓ10²³ atoms

4 0
3 years ago
Read 2 more answers
ANSWER ASAP PLEASE
user100 [1]
Density is equal to mass divided by volume so the densest object will be the object that has the largest mass in the smallest area. In this case object A is the densest with a density of 10g/cm^3. I hope this helps. Let me know if anything is unclear.
3 0
3 years ago
Nitrogen gas exerts a pressure of 846mmhg. When the pressure is changed to 2.5atm its volume is 63.9l. What was the original vol
Aloiza [94]

Explanation:

760 \: mmHg \:  =  \: 1 \: atm \\ 846 \: mmHg \:  =  \: ( \frac{846}{760} ) \: atm \\  = 1.1 \: atm \\  \\ P _{1} V _{1} = P _{2}V _{2} \\ 1.1 \times V _{1}  = 2.5 \times 63.9 \\ V _{1}  =  \frac{2.5 \times 63.9}{1.1}  \\ V _{1}  = 145.2 \: litres

3 0
3 years ago
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