Question

Solve: 2x^2-28x+106=0

Answer 1

Use the quadratic formula to find the solutions.

−b±√b2−4(ac)2a-b±b2-4(ac)2a

subtite the values

a=2a=2,

b=−28b=-28, and

c=98c=98 into the quadratic formula and solve for

xx.28±√(−28)2−4⋅(2⋅98)2⋅228±(-28)2-4⋅(2⋅98)2⋅2Simplify.

Simplify the numerator.

x=28±02⋅2x=28±02⋅4 Multiply

22 by 22.x=28±04x=28±04 Simplify

28±0428±04.x=284x=284Divide 2828 by 44.x=7x=7

The final answer is the combination of both solutions.

x=7x=7 Double roots