All categories

3 years ago

Which pair of numbers has a product of -24 and a sum of 10?

Mathematics

2 answers:

muminat3 years ago

6 0

Answer:

-2;12

Step-by-step explanation:

it's too easy!

3241004551 [841]3 years ago

5 0

The answer of question is -2 and 12

You might be interested in

For the equation -4y = 8x , what is the constant of variation?

Inga [223]

-4y = 8x

Divide both sides by -4

y = -2x

This is in the form of y = kx, where k is the constant of variation.
y = kx is the direct

That means, k = -2.

The constant of variation is B. -2.

7 0

3 years ago

Read 2 more answers

PLEASE HURRY In order to solve the system of equations below, Juana multiplies each equation by a constant to eliminate the y te

Doss [256]

Answer:

16x -12y = 4

15x +12y = 27

Step-by-step explanation:

4x-3y = 1

5x+4y=9

Multiply the first equation by 4

16x -12y = 4

Multiply the second equation by 3

15x +12y = 27

7 0

3 years ago

Read 2 more answers

Write a simplified expression for the

Simora [160]

Answer: 3.75 + - 7

Step-by-step explanation:

1.5x - 3 + 1.5x - 3 + 0.75x - 1

1.5x + 1.5x + 0.75x - 3 + - 3 + - 1

3.75x + - 7

3 0

3 years ago

In a right triangle, the length of one leg is 6 units. The length of the other leg is 8 units. What is the length of the hypoten

lozanna [386]

$hypotenuse = \sqrt{6^2+8^2}= \sqrt{36+64}= \sqrt{100}=10 \ units$

7 0

3 years ago

Read 2 more answers

Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th

denpristay [2]

Answer:

(1) Correct option is B.

(2) Correct option is C.

Step-by-step explanation:

The information provided is:

$n_{1}=200,\ \bar x_{1}=22.7,\ s_{1} = 4.5\\n_{2}=200,\ \bar x_{2}=19.7,\ s_{2} = 4.3$

The (1 - <em>α</em>)% confidence interval for the difference between two mean is:

$CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_[2}-2}\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}} }$

The critical value of <em>t</em> is:

$\alpha /2=0.05/2=0.025$

degrees of freedom $=n_{1}+n_{2}-2=200+200-2=398$

$t_{\alpha/2, n_{1}+n_{2}-2}=t_{0.025, 398}=1.96$

Compute the 95% confidence interval for the difference between two mean as follows:

$CI=22.7-19.7\pm 1.96\sqrt{\frac{4.5^{2}}{200}+\frac{4.3^{2}}{200} }\\=3\pm0.8624\\=(2.1376, 3.8624)\\\approx(2.14, 3.86)$

Thus, the 95% confidence interval, (2.14, 3.86) implies that the true mean difference value is contained in this interval with probability 0.95.

Correct option is B.

The null value of the difference between means is 0.

As the value 0 is not in the interval this implies that there is a difference between the two means, concluding that priming does have an effect on scores.

Correct option is C.

4 0

3 years ago