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iogann1982 [59]
2 years ago
6

The total cost of a truck rental, y, for x days, can be modeled by y=24x+39. What is the rate of change for this function?

Mathematics
1 answer:
padilas [110]2 years ago
3 0

Answer:

24 per day

Step-by-step explanation:

'x' = days, so since 24 is with x, the rate of change is 24

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Samuel's car usually takes about 12.5 gallons of gas to fill it up when it's empty while driving through Canada Samuel notice th
nika2105 [10]

Answer: 47.4 liters

Step-by-step explanation:

From the question, we are informed that Samuel's car usually takes about 12.5 gallons of gas to fill it up when it's empty and while in Canada, he noticed that one liter is equivalent to 0.264 gallons.

The number of liters it'll take to fill Samuels car will be:

= 12.5/0.264

= 47.4 litres

7 0
3 years ago
Y = x +4<br> 3x + y = 16
Vesna [10]

Answer:

x= 3 while fo y = 7 that's the answer

5 0
3 years ago
Help me decrease 25 by 30%
Marysya12 [62]

Step-by-step explanation:

Percentage decrease = 30% × 25

New value = 25 - Percentage decreaseNew value =

25 - Percentage decrease =

25 - (30% × 25) =

25 - 30% × 25 =

(1 - 30%) × 25 =

(100% - 30%) × 25 =

70% × 25 =

70 ÷ 100 × 25 =

70 × 25 ÷ 100 =

1,750 ÷ 100 =

17.5

Absolute change (actual difference) =

New value - 25 =

17.5 - 25 =

- 7.5

8 0
2 years ago
Read 2 more answers
Help!! 50 points and brainliest!
Viktor [21]

Answer:

Second choice:

x=2t

y=4t^2+4t-3

Fifth choice:

x=t+1

y=t^2+4t

Step-by-step explanation:

Let's look at choice 1.

x=t+1

y=t^2+2t

I'm going to subtract 1 on both sides for the first equation giving me x-1=t. I will replace the t in the second equation with this substitution from equation 1.

y=(x-1)^2+2(x-1)

Expand using the distributive property and the identity (u+v)^2=u^2+2uv+v^2:

y=(x^2-2x+1)+(2x-2)

y=x^2+(-2x+2x)+(1-2)

y=x^2+0+-1

y=x^2

So this not the desired result.

Let's look at choice 2.

x=2t

y=4t^2+4t-3

Solve the first equation for t by dividing both sides by 2:

t=\frac{x}{2}.

Let's plug this into equation 2:

y=4(\frac{x}{2})^2+4(\frac{x}{2})-3

y=4(\frac{x^2}{4})+2x-3

y=x^2+2x-3

This is the desired result.

Choice 3:

x=t-3

y=t^2+2t

Solve the first equation for t by adding 3 on both sides:

x+3=t.

Plug into second equation:

y=(x+3)^2+2(x+3)

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

y=(x^2+6x+9)+(2x+6)

y=(x^2)+(6x+2x)+(9+6)

y=x^2+8x+15

Not the desired result.

Choice 4:

x=t^2

y=2t-3

I'm going to solve the bottom equation for t since I don't want to deal with square roots.

Add 3 on both sides:

y+3=2t

Divide both sides by 2:

\frac{y+3}{2}=t

Plug into equation 1:

x=(\frac{y+3}{2})^2

This is not the desired result because the y variable will be squared now instead of the x variable.

Choice 5:

x=t+1

y=t^2+4t

Solve the first equation for t by subtracting 1 on both sides:

x-1=t.

Plug into equation 2:

y=(x-1)^2+4(x-1)

Distribute and use the binomial square identity used earlier:

y=(x^2-2x+1)+(4x-4)

y=(x^2)+(-2x+4x)+(1-4)

y=x^2+2x+-3

y=x^2+2x-3.

This is the desired result.

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3 years ago
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Umnica [9.8K]
How to comparan? Not sure
5 0
3 years ago
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