All categories

3 years ago

A null hypothesis can only be rejected at the 5% significance level if and only if:

Mathematics

1 answer:

ozzi3 years ago

6 0

Answer:

Option (B) a 95% confidence interval does not include the hypothesized value of the parameter

Step-by-step explanation:

Alpha, α = 0.05

We conduct a hypothesis test at 5% significance level.

The null hypothesis will be rejected when

Option (B) a 95% confidence interval does not include the hypothesized value of the parameter

When a 95% confidence interval is constructed,it contains all the possible values for the parameter being estimated.

If the value of the parameter stated in the null hypothesis is contained in the 95% confidence interval, then we fail to reject the null hypothesis 0.05 level and accept it.

If the value stated in the null hypothesis is not in the interval, then we fail to accept the null hypothesis and reject the null hypothesis at the 0.05 level.

You might be interested in

Find the variance of the given data rounded to the nearest hundredth 3,4,5,7,10,12,15

True [87]

Answer:

(3 + 4 + 5 + 7 + 10 + 12 + 15)/7 = 8

(3^2 + 4^2 + 5^2 + 7^2 + 10^2 + 12^2 + 15^2)/7 - 8^2 = 17.14285714

4 0

4 years ago

John reads an equal number of pages of a book every week. The graph below shows the number of pages of the book left to read, y,

Genrish500 [490]

Answer:

John reads an equal number of pages of a book every week. The graph below shows the number of pages of the book left to read, y, after x weeks. The equation best models the relationship between x and y is y = −25x + 175

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The table shows a proportional relationship

AlekseyPX

Answer:

where the table ?

Step-by-step explanation:

6 0

3 years ago

What shape doesn’t have a rectangular face

GrogVix [38]

Answer:

Step-by-step explanation:

a traingle because it doesnt use any rectangular faces it only uses traingular forms or even a speer a speer has no rectangular sides

4 0

2 years ago

A rescue helicopter flew from its home base for 35 kilometers on a course of 330 degrees to pick up an accident victim. It then

artcher [175]

I've drawn a triangle to represent the journey (see attached.

The angle from Home to Victim to Hospital is:

a = $90 - (360 - 330) = 90- 30 = 60^o$

Using the cos rule, we can solve for the length x:

$a^2 = b^2 +c^2 - 2bccosA
\\x^2 = 35^2+25^2-2(35)(25)cos60
\\x^2 = 1850 - 875
\\x^2 = 975
\\x = \sqrt{975}
\\x = 31.2249...$

Using the cos rule, we can solve for angle b:

$a^2 = b^2 +c^2 - 2bccosA
\\35^2 = 31.22...^2+25^2-2(31.22...)(25)cosb
\\1225 = 975 + 625 - 1561.249...cosb
\\-375 = -1561.249...cosb
\\b = cos^{-1}( \frac{-375}{-1561.249...}) 
\\b = 76.1...$

So the bearing the helicopter has to travel is:

270 - 76.1 = <u>193.9 degrees (1 dp)</u>

And the distance it travels is <u>31.2 km (1 dp)</u>

5 0

3 years ago