A null hypothesis can only be rejected at the 5% significance level if and only if:
1 answer:
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<h3>Answer: Largest value is a = 9</h3>
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Work Shown:
b = 5
(2b)^2 = (2*5)^2 = 100
So we want the expression a^2+3b to be less than (2b)^2 = 100
We need to solve a^2 + 3b < 100 which turns into
a^2 + 3b < 100
a^2 + 3(5) < 100
a^2 + 15 < 100
after substituting in b = 5.
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Let's isolate 'a'
a^2 + 15 < 100
a^2 < 100-15
a^2 < 85
a < sqrt(85)
a < 9.2195
'a' is an integer, so we round down to the nearest whole number to get
So the greatest integer possible for 'a' is a = 9.
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Check:
plug in a = 9 and b = 5
a^2 + 3b < 100
9^2 + 3(5) < 100
81 + 15 < 100
96 < 100 .... true statement
now try a = 10 and b = 5
a^2 + 3b < 100
10^2 + 3(5) < 100
100 + 15 < 100 ... you can probably already see the issue
115 < 100 ... this is false, so a = 10 doesn't work
Answer:
The equation in the slope-intercept form is y = + -6 ⇒ C
Step-by-step explanation:
The slope-intercept form of the linear equation is
y = m x + b, where
- m is the slope of the line
- b is the y-intercept
∵ The equation is 13x - 3y = 18
→ At first move x from the left side to the right side by subtracting 13x
from both sides
∴ 13x - 13x - 3y = 18 - 13x
∴ - 3y = 18 - 13x
→ Make the coefficient of y equal 1 by dividing both sides by -3
∵
∴ y = -6 - ()
→ Remember (-)(-) = (+)
∴ y = -6 +
→ Switch the two terms of the right side
∴ y = + - 6
∴ The equation in the slope-intercept form is y = + -6