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3 years ago

How do I do this problem

Mathematics

2 answers:

emmasim [6.3K]3 years ago

8 0

R =6 s= 1/4
6×1/4+14×1/4=5

KiRa [710]3 years ago

4 0

R=6 & s=1/4
Just plug that in to the equation.
6+1/4 +14(1/4)
6.25 +3.5
9.75 or 39/4

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Solve for y. y = 93 degrees y = 103 degrees y = 23 degrees y = 33 degrees

Gelneren [198K]

The two angles are vertical angles and are identical.

Set them equal to each other and solve for y:

5y = 115

Divide both sides by 5:

y = 115/5

y = 23

Answer: y = 23 degrees.

6 0

3 years ago

Susan currently has an account balance of $1,336.60. Her initial deposit on the account was $820 and it earned 4.5% simple inter

emmasim [6.3K]

The correct option will be : 14 years

Explanation

Current account balance of Susan is $1,336.60 and her initial deposit was $820

So, the amount of interest earned $= 1336.60-820= 516.60$ dollar

Formula for Simple Interest is: $I= P*r*t$ , where $I$ is the amount of interest, $P$ is the initial amount, $r$ is the rate of interest in decimal and $t$ is the time duration in years.

Here, $I= 516.60, P= 820, r=4.5$ % $= 0.045$

Now according to the above formula, we will get...

$I= P*r*t\\\\ 516.60=820*0.045*t\\\\ 516.60=36.90*t\\\\ t=\frac{516.60}{36.90}= 14$

So, Susan has held the account for 14 years.

3 0

3 years ago

9. One box has a surface area of 96 cm2 and a height of 4 cm.

ss7ja [257]

Answer:

2,645

Step-by-step explanation:

I hope this helps and you really are smart

8 0

3 years ago

NEED HELP PLEASE ASAP

ivann1987 [24]

Answer: 45?

Step-by-step explanation: because a perfect corner is 90 degrees so if you split that, you will get 45!

6 0

2 years ago

A rectangular field is 75 yards wide and 105 yards long

nika2105 [10]

Answer:

width = 72 yards

length = 108 yards

Step-by-step explanation:

Given:

Width = 75 yards
Length = 105 yards

Area of the field with the given values:

$\begin{aligned}\textsf{Area of a rectangle}&=\sf width \times length\\& = \sf 75 \times 105\\& = \sf 7875\:\: yd^2\end{aligned}$

To maintain the same perimeter, but change the area, either:

decrease the width and increase the length by the same amount, or
increase the width and decrease the length by the same amount.

In geometry, length pertains to the longest side of the rectangle while width is the shorter side. Therefore, we should choose:

decrease the width and increase the length by the same amount.

Define the variables:

Let x = the amount by which to decrease/increase the width and length.

Therefore:

$\implies \sf width \times length < 7875\:\:yd^2$

$\implies (75-x)(105+x) < 7875$

Solve the inequality:

$\begin{aligned}(75-x)(105+x) & < 7875\\7875-30x-x^2 & < 7875\\-x^2-30x & < 0\\-x(x+30) & < 0\\x(x+30) & > 0\\\implies x & > 0 \:\: \textsf{ or }\:\:x < - 30\end{aligned}$

Therefore, as distance is positive only and the maximum width is 75 yd (since we are subtracting from the original width):

$\begin{cases}\textsf{width} = 75 - x\\\textsf{length} = 105 + x\end{cases}$

$\textsf{where } 0 < x < 75$

Therefore, to find the width and length of another rectangular field that has the same perimeter but a smaller area than the first field, simply substitute a value of x from the restricted interval into the found expressions for width and length:

Example 1:

Let x = 3

⇒ Width = 75 - 3 = 72 yd

⇒ Length = 105 + 3 = 108 yd

⇒ Perimeter = 2(72 + 108) = 360 yd

⇒ Area = 72 × 108 = 7776 yd²

Example 2:

Let x = 74

⇒ Width = 75 - 74 = 1 yd

⇒ Length = 105 + 74 = 179 yd

⇒ Perimeter = 2(1 + 179) = 360 yd

⇒ Area = 1 × 179 = 179 yd²

4 0

1 year ago

Read 2 more answers