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ipn [44]
3 years ago
11

ABC is an isosceles triangle with AB=BC ACD is a straight line work out the size of BCD

Mathematics
1 answer:
rusak2 [61]3 years ago
5 0

Answer:

Triangle ABC is isosceles, with AC = BC. Angle ACD= 620 BCD is a straight line. 180-118=62 62:2-31 x= 31.

Step-by-step explanation:

plz mark as brainiest

hope it helps

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Solve the triangle. A = 51°, b = 14, c = 6, I'll give 20 points
ankoles [38]

Answer:

Step-by-step explanation:

We have that

A = 51°, b = 14, c = 6

step 1

find the value of a

Applying the law of cosines

a²=c²+b²-2*c*b*cos A

a²=6²+14²-2*6*14*cos 51-------> 126.27

a=11.2

we know that

The sum of the lengths of any two sides of a triangle is greater than the length of the third side.

we have

a=11.2

b=14

c=6

so

(a+b) > c-------------> (11.2+14)=25.2

25.2 > 6-----> is not correct

therefore

the answer is the option

a. No triangles possible

I don't know if i am right sorry if this is wrong

7 0
3 years ago
2143.57333 whole number
poizon [28]

Answer:

No, this is not a whole number. See how it has a decimal point? That's how you know if it is a decimal.

:)

4 0
3 years ago
Write an equation in slope-intercept form for the line with y-intercept −5 and slope −2/5
riadik2000 [5.3K]

Answer:

\large\boxed{y=-\dfrac{2}{5}x-5}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

We have

m=-\dfrac{2}{5},\ b=-5

Substitute:

y=-\dfrac{2}{5}x+(-5)}=-\dfrac{2}{5}x-5

8 0
3 years ago
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soldier1979 [14.2K]

Answer:

see explanation

Step-by-step explanation:

The area (A) of a square is calculated as

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Here s = x + 2 and A = 7, thus

(x + 2)² = 7 ← expand left side using FOIL

x² + 4x + 4 = 7 ( subtract 4 from both sides )

x² + 4x = 3 ← as required

4 0
3 years ago
Distance from the x-axis is 2
lapo4ka [179]
It would be 2,0 for the x and y
6 0
3 years ago
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