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cupoosta [38]
3 years ago
11

Point K is graphed on a number line at 3. Point L is 11 units away from point K on the number line.

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
6 0
The points would be either: -8 or 14
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Simplify 7x^2+ 5x+4x answer pls
SIZIF [17.4K]

Answer:

7x^2+9x

Step-by-step explanation:

Hope this helps...

7x^2+(5x+4x)=

7x^2=9x

4 0
3 years ago
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Assuming that π = 3.14, how much air will it take to fill a sports ball with a radius of 6 cm?
madam [21]

Answer:

I would need more information but I believe its A

Step-by-step explanation:

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3 years ago
Y+5=-11<br> What does y equal?
Brut [27]
Y+5=-11
   -5    -5
Y= -16

Answer:-16
8 0
3 years ago
Suppose a certain type of fertilizer has an expected yield per acre of mu 1 with variance sigma 2, whereas the expected yield fo
mart [117]

Answer:

See the proof below.

Step-by-step explanation:

For this case we just need to apply properties of expected value. We know that the estimator is given by:

S^2_p= \frac{(n_1 -1) S^2_1 +(n_2 -1) S^2_2}{n_1 +n_2 -2}

And we want to proof that E(S^2_p)= \sigma^2

So we can begin with this:

E(S^2_p)= E(\frac{(n_1 -1) S^2_1 +(n_2 -1) S^2_2}{n_1 +n_2 -2})

And we can distribute the expected value into the temrs like this:

E(S^2_p)= \frac{(n_1 -1) E(S^2_1) +(n_2 -1) E(S^2_2)}{n_1 +n_2 -2}

And we know that the expected value for the estimator of the variance s is \sigma, or in other way E(s) = \sigma so if we apply this property here we have:

E(S^2_p)= \frac{(n_1 -1 )\sigma^2_1 +(n_2 -1) \sigma^2_2}{n_1 +n_2 -2}

And we know that \sigma^2_1 = \sigma^2_2 = \sigma^2 so using this we can take common factor like this:

E(S^2_p)= \frac{(n_1 -1) +(n_2 -1)}{n_1 +n_2 -2} \sigma^2 =\sigma^2

And then we see that the pooled variance is an unbiased estimator for the population variance when we have two population with the same variance.

8 0
3 years ago
I need help quick i need to turn this in today
Alex

Answer:

I am pretty sure it is d, if i am wrong, I am sorry.

Step-by-step explanation:

?

3 0
3 years ago
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