3 years ago

Which triangles can not be proved congruent?#37

1 answer:

3 0

B is the answer because it does not give information for the third side. We cannot assume it is equal because it is not a right triangle.

You might be interested in

Quadrilateral ABCD is given, the interior angle at vertex B is 97 degrees and the exterior angle at vertex A is 88 degrees. Line

Citrus2011 [14]

Answer:

angle 1 = 83°

angle 2 = 88°

Step-by-step explanation:

angle 1 and angle on vertex B are

pair of co interior angles ( whose sum = 180° )

so, angle 1 + angle B = 180°

angle 1 = 180° - angle B

angle 1 = 180° - 97° = 83°

hence, angle 1 = 83°

but, angle 2 and exterior of vertex A forms alternate interior angle pair ,

so , angle 2 = angle A = 88°

i hope you got it ....

5 0

3 years ago

The spray from a sprinkler reaches 21 feet from the sprinkler and creates a circle as it spins. What is the circumference of the

lina2011 [118]

C=πd

r=21

d=42

C=132 ft, and D is your final answer. Hope it help!

4 0

3 years ago

Which expression is equivalent to -28x + 36 A) -4(7x - 9) or B) 7(-4x +6)

Aleonysh [2.5K]

Answer:

Answer would be A. -4(7x-9)

4 0

3 years ago

Read 2 more answers

Please help w/ composition of functions. I did 3√14-(-11) -8 and got 7 as my answer and would appreciate verification that it's

dangina [55]

SOLUTION

We were given

$\begin{gathered} f(c)=3c-8\text{ and } \\ g(c)=\sqrt[]{14-c} \\ We\text{ want to find } \\ (fog)(-11) \end{gathered}$

First we will find

$\begin{gathered} f(g(c)\text{ we have } \\ f(g(c)=3(\sqrt[]{14-c})-8 \end{gathered}$

Now

$\begin{gathered} (fog)(-11)\text{ becomes } \\ (fog)=3(\sqrt[]{14-c})-8 \\ (fog)(-11)=3(\sqrt[]{14-(-11})-8 \\ =3\sqrt[]{14+11}-8 \\ =3\sqrt[]{25}-8 \\ (3\times5)-8 \\ =15-8 \\ =7 \end{gathered}$

Hence, the answer is 7

7 0

1 year ago

Determine the value of X D o,k (X,9) —> (-10,-6) A. 5 B. 7 C. 12 D. 15

Citrus2011 [14]

Answer:

Step-by-step explanation:

that is the answer if it may help you

4 0

3 years ago