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3 years ago

A rectangular sandbox has a width of 5 feet.The sandbox is 5 times as long as it is wide. What is the perimeter of the sandbox?

Mathematics

1 answer:

AveGali [126]3 years ago

8 0

Wide is 5 x 5 = 25 feet;
P = 2 x width + 2 x wide = 10 + 50 = 60 feet;

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Need HELP PLS PIC ATTACHED

Vera_Pavlovna [14]

Answer:

$4x^{2}$ -13x+10

Step-by-step explanation:

(4x+5)(x-2)

Multiply each term in the first parenthesis by each term in the second (foil)

Step 1: Expand it by writing out each multiplication. I added a picture showing which order to do it. (go in order of green, red, blue, yellow.) (you can remember this as first, outside, inside, last.)

When you expand it'll look like: 4x⋅x+4x⋅-2-5x-5⋅-2

Step 2: Calculate product

4x⋅x+4x⋅-2-5x-5⋅-2 (for the 4x⋅x it would be written like $4x^{2}$ )

$4x^{2}$ +4x⋅-2-5x-5⋅-2

$4x^{2}$ +4x⋅-2-5x-5⋅-2 (4x⋅-2 becomes -8x) (multiply 4x times -2)

$4x^{2}$ -8x-5x-5⋅-2

$4x^{2}$ -8x-5x-5⋅-2 (-5⋅-2 becomes +10) (multiply -5 times -2)

$4x^{2}$ -8x-5x+10

Step 3: collect like terms

$4x^{2}$ -8x-5x+10 (-8x-5x becomes -13x) (-8x times -5x)

$4x^{2}$ -13x+10 is the most simplified so it should be your final answer

4 0

1 year ago

Equation using the quadratic fromula for 0.05x^2 + 1.1x = 250

Anuta_ua [19.1K]

Answer:

x=60.56, x=-82.56

Step-by-step explanation:

Solve using quadratic formula

Formula is

$x=\frac{-b+-\sqrt{b^2-4ac}}{2a}$

0.05x^2 + 1.1x = 250

Subtract 250 on both sides

0.05x^2 + 1.1x - 250=0

a= 0.05, b=1.1 , c=-250

Plug in the values in the formula

$x=\frac{-1.1+-\sqrt{(1.1)^2-4(0.05)(-250)}}{2(0.05)}$

$x=\frac{-1.1+-7.156116265}{0.1}$

Now make two equations , one with + and one with -

then we solve for x

$x=\frac{-1.1+7.156116265}{0.1}$

x=60.56

$x=\frac{-1.1-7.156116265}{0.1}$

x=-82.56

3 0

3 years ago

Given a sample mean difference of 23, a standard error of 4.2, and a critical t value of 2.262, what are the values for the conf

erastova [34]

Answer: (13.4996, 32.5004)

Step-by-step explanation:

The confidence interval for mean difference is given by :-

$(\overline{x}_1-\overline{x}_2)\pm t^*\times SE$ ,

where $(\overline{x}_1-\overline{x}_2)$ = sample mean difference .

$t^*$ = critical t value (two-tailed)

SE= Standard error.

Given : $(\overline{x}_1-\overline{x}_2)=23$

$t^*=2.262$

SE= 4.2

Now, the confidence interval for mean difference will be :-

$23\pm (2.262)\times (4.2)\\\\= 23\pm9.5004\\\\=(23-9.5004,\ 23+9.5004)\\\\=(13.4996,\ 32.5004)$

Hence, the required confidence interval : (13.4996, 32.5004)

8 0

3 years ago

Usqqe format HTH to mean that the first toss is heads, the second is tails and the third is heads more than one element in the s

Scrat [10]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: State the number of outcomes possible for three tossing of a coin

Since a coin has two possible outcomes and is tossed three times, the total outcomes will be:

$\begin{gathered} 2^3=8 \\ 8\text{ outcomes} \end{gathered}$

STEP 2: Find the number of sample spaces for the three tosses

STEP 3: Get the outcomes of the events for which the second toss is tails

Hence, the answers are given as:

Sample Space:

$\lbrace HHH,HHT,HTH,HTT,THH,THT,TTH,TTT\rbrace$

The event that the second toss is tails:

$\lbrace HTH,HTT,TTH,TTT\rbrace$

4 0

1 year ago

Two cities are 45 miles apart. Two trains, with speeds of 70 mph and 60 mph, leave the two cities at the same time so that one i

Sergio039 [100]

8.57 for the first one and, I’m not sure a bout the second time though

7 0

3 years ago