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kodGreya [7K]
3 years ago
5

^ please help me____________

Mathematics
2 answers:
MissTica3 years ago
8 0
All you have to do is take half of 6x, square it and add it to both sides. It will look like this. x^2+6x+9=16+9. Now all you do is simplify to get (x+3)^2=25.
DaniilM [7]3 years ago
3 0
X^2 + 6x - 16 =0
The two numbers that satisfy the condition quadratics have is
1. They must add to 6
2, They must multiply to - 16 

All quadratics have to satisfy these two things.
The only numbers that will are 8 and - 2
So the factors are
(x - 8)(x + 2) = 0
x - 8 = 0
x = 8

and

x + 2 = 0
x = - 2
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3 years ago
Solve for x in the equation 2x^2+14x+17=-96
goblinko [34]
2x^{2}+14x+17=-96 \newline
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3 years ago
Graph the system of linear inequalities, please explain the process in solving this problem so I know how to do ones similar to
astra-53 [7]

Answer:

See attached. (Both inequalities graph to the same region.)

Step-by-step explanation:

To graph an inequality, you first replace the inequality symbol by an equal sign. Then you graph the line (or curve) described by the equation. If the inequality symbol includes the "or equal to" case, then the line (or curve) is solid and is part of the solution set. If not, then the line (or curve) is dashed and is <em>not part of the solution set</em>.

Here, the line x+y=5, will bound the solution set, but is not part of it.

Note that the line -x -y = -5 (from the second inequality) is the same ilne.

_____

After you have graphed the boundary of the solution region, you need to determine which side of the boundary has the solutions. I find it easy to do this by locating an x- or y-term with a positive coefficient and seeing which side of the inequality symbol that lies on. Here, both the x-term and the y-term lie on the "is greater than" side of the symbol, so the half-plane is shaded above and to the right of the line, where x- and y-values are greater than they are on the line.

In the second inequality, you can multiply the whole thing by -1 to get

... x + y > 5 . . . . same as the first inequality

or you can add (x+y) to both sides to get

... 0 < -5 +x +y

Once again, the x- and y-values that satisfy this are greater than those that are on the boundary line.

_____

The graph seems to show only one equation. Both are there, but the dashed blue line sits on top of the dashed red line, so you can't see it. The purple shading indicates both red and blue shading in the same area.

===== =====

Of course you graph the boundary line the way you would any linear equation. In this form, it is not too difficult to see that both the x- and y-intercepts are 5. (When x=0, y=5; and when y=0, x=5 for the boundary line's equation x+y=5.) Draw the dotted line through these intercept points, add shading above, and you have your graph.

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3 years ago
Carl is boarding a plane he has two checked bags of equal weight and backpack that weighs 4 kg the total weight of Carl’s backpa
Tresset [83]

Answer:

Carl's checked bags way 15.5 kilograms each.

Step-by-step explanation:

35-4=31 -> 31÷2=15.5

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