2 years ago

Suppose that ,LV YM, YV = 11 cm, and ⊙L has a diameter of 26 cm. Find YM.

1 answer:

8 0

Answer: I just had this on a test the answer is [ 22cm ]

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Mrrafil [7]

X^4 - 4x^3 - 9x^2 + 36x = 0
x(x^3 - 4x^2 - 9x + 36) = 0
x(x^2(x - 4) - 9(x - 4) = 0
x(x + 3)(x - 3)(x - 4) = 0

the zeroes are -3, 0, 3, 4 Answer

3 0

2 years ago

stealth61 [152]

The numbers on the left represent 10 times that number

The numbers on the right are added to the end of the number on the left so

3I1=31 and 4I8=48 and 3I 1 1 2= 31 31 32

4 0

2 years ago

ZanzabumX [31]

The answer to this question is 48.

7 0

3 years ago

photoshop1234 [79]

For this case, the first thing we must do is define a variable.

We have then:

x: unknown number

We now write the expression that models the problem:

$\frac{\frac{4}{9}}{x} = 12$

From here, we clear the value of x.

We have then:

$\frac{4}{9}=12x$

$\frac{4}{9(12)}=x$

$x=\frac{4}{108}$

$x=\frac{1}{27}$

Answer:

4/9 divided by 1/27 equals 12

6 0

2 years ago

dmitriy555 [2]

Jackie spent $39.15 on the dress.

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3 years ago