Si f(x)=2x^{2}−3x+1 y g(x)=x−3. Entonces (f∘g)(−1) es:

Find the area of the rhombus. A= square units

Olin [163]

The answer should be 24 square units.

5 is the hypotenuse and the one we need is the base and the height. They gave us the height, which was 6 in total but 3 for the triangle. But we needed to find the base.

In order to do that, we need to use the Pythagorean Theorem.

a^2+b^2=c^2

3^2+b^2=5^2

9+b^2=25

Subtract 9 from both sides

b^2=16

Then square root both sides.

b=4.

Now that we have the base, you can then find the area of the triangle.

BH/2
4*3/2
12/2
6

So one triangle equals to 6. Then multiply that by 4 to find the area of the rhombus. Which would be 24 square units.

7 0

3 years ago

Can someone help with these two questions? dont worry if its wrong!

nevsk [136]

Answer:

1)8&3/4 CUP FLOUR

2)26 KIDS CAN GO ..

Step-by-step explanation:

1) one batch=2 1/2 cup flour

therefore batch required in 3 1/2 batch= 5/2×7/2=35/4

=8&3/4cup flour

2)No. of kids can go for $60=8

therefore,no. of kids can go in $1=8/60

Therefore,no. of kids can go in $195=8/60×195=26 kids.

6 0

2 years ago

Read 2 more answers

Clayton is shopping for a new shower. He is comparing the water usage of cach as he is shopping .

Jlenok [28]

What else ? Is that it ?

7 0

2 years ago

uppose germination periods, in days, for grass seed are normally distributed and have a known population standard deviation of 2

natka813 [3]

Answer: 0.701

Step-by-step explanation:

Formula : $EBM =z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$ , where $\alpha=$ significance level , $\sigma =$ Population standard deviation, n= sample size.

As per given, n= 22

$\sigma = 2$

Critical z- value for 90% confidence level : $z_{\alpha/2}=1.645$

Then,

$EBM =(1.645)\dfrac{2}{\sqrt{22}}\\\\=(1.645)\dfrac{2}{4.690416}\\\\\approx0.701$

Hence , error bound (EBM) of the confidence interval with a 90% confidence level= ± 0.701

5 0

2 years ago

The weight of a beg of pears at the local market averages 8 pounds with a standard deviation of 0.5 pound. The weight of all the

Blababa [14]

Mean weight of the bag of pears = u = 8 pounds
Standard deviation = s = 0.5 pounds

We have to find what percentage of bags of pears will weigh more than 8.25 pounds. This can be done using the z score.

We have to convert x = 8.25 to z scores, which will be:

$z= \frac{x-u}{s}= \frac{8.25-8}{0.5}$

z score = 0.5

From the z table, the probability of z score being greater than 0.5 is 0.3085

Therefore, the probability of a bag to weigh more than 8.25 pounds is 0.3085

Thus 0.3085 or 31% (rounded to nearest integer) of bags of pears will have weight more than 8.25 pounds at the local market.

4 0

2 years ago