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erastovalidia [21]
4 years ago
7

Andrew sold 45 tickets to the school play and Sara sold 40 tickets. What is the best ratio of the number of tickets Andrew sold

to the number of tickets Sara sold?
Mathematics
2 answers:
kolbaska11 [484]4 years ago
7 0
9/8 would be the fraction.
Readme [11.4K]4 years ago
3 0
9/8 is the fraction.
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Which polygons are NOT quadrilaterals? Select THREE that apply.
Afina-wow [57]

Answer:

a cylinder, a sphere, and that little half sphere thing, oh and a triangular pyramid

Step-by-step explanation:

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Selecting an SUV with a blue exterior
frozen [14]

The answer is straightforward, by the "rule of product":

There are

3×8×2=48

3×8×2=48

different combinations (distinct possible cars) that can be created.

There 33 choices for body style; 88 choices for exterior colors, and 22 choices of interior color schemes:

Since each of these choices are independent (the choice of body style doesn't depend on exterior or interior color, e.g.) we multiply the number of choices for each quality to obtain: 3×8×2=483×8×2=48 distinct ways to create a car

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2 years ago
Find the area of the figure. Round to the nearest tenth if necessary. 5.5 ft 6 ft 8 ft ​
bogdanovich [222]

Answer:

21 savage

Step-by-step explanation:

8 0
3 years ago
Please help me on this’ gracias
blondinia [14]

Answer:

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6 0
3 years ago
Read 2 more answers
A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri
GuDViN [60]

Answer:

1.\frac{dy}{dt}=ky

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

\frac{dy}{dt}=Number of bacteria per unit time

\frac{dy}{dt}\proportional y

\frac{dy}{dt}=ky

Where k=Proportionality constant

2.\frac{dy}{y}=kdt,y'(0)=100

Integrating on both sides then, we get

lny=kt+C

We have y(0)=200

Substitute the values then , we get

ln 200=k(0)+C

C=ln 200

Substitute the value of C then we get

ln y=kt+ln 200

ln y-ln200=kt

ln\frac{y}{200}=kt

\frac{y}{200}=e^{kt}

y=200e^{kt}

Differentiate w.r.t

y'=200ke^{kt}

Substitute the given condition then, we get

100=200ke^{0}=200 \;because \;e^0=1

k=\frac{100}{200}=\frac{1}{2}

y=200e^{\frac{t}{2}}

Substitute t=2

Then, we get y=200e^{\frac{2}{2}}=200e

y=200(2.718)=543.6=543.6

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0
4 years ago
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