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masha68 [24]
3 years ago
6

What is a correct first step in solving 5-2x<8x-3

Mathematics
2 answers:
Crazy boy [7]3 years ago
5 0

the first step would to get rid of the coefficients, in my case i moved the -2x to the other side and added it to the 8x to get 10x

Lubov Fominskaja [6]3 years ago
4 0

The correct first step is to add 2x to both sides. Then, add 3 to both sides. You will then get 8<10x. Finally, divide both sides by 10. You get x>8/10. You can simplify that to x>4/5.

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5 0
3 years ago
Solve 5r2 – 12 = 68. {±4} {±5} {±3} {±6}
sashaice [31]

Hey there!

Assuming you meant

5r^2 - 12 = 68

If so, follow these steps so it can be a little bit easier to solve

Firstly, we have to add by 12 on each of your sides

5r^2 -12 +12 \\ \\ 68 + 12

5r^2 = 5r^2 \\ \\ 68 + 12 = 80

We get: 5r^2 =80

Now, we have divide by 5 on each of your sides

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Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

3 0
3 years ago
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