1) Triangle QRT, where q = 32.4 ft, r = 29.8 ft, t = 42.1 ft
No this cannot make a second triangle
2) Triangle ABC, where B = 62°, a = 11.52 m, c = 19.34 m
No this cannot make a second triangle
3) Both of the triangles cannot make a second triangle
<h3>How does law of sine work</h3>
The following is a detailed explanation of the sine law: In a triangle, side "a" divided by angle sine "a" equals side "b" divided by angle sine "b" equals side "c" divided by angle sine "c."
The formula for law of sine is written as
Sine A a = Sine B/ b = Sine C / c
These law helps in determining the given angles and sides
For the situation given; both cannot be used to make a second triangle
Learn more about conditions Infinite number of triangles at:
brainly.com/question/29637739
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Start by reviewing your knowledge of natural logarithms. If we take the ln of both sides we get e^z=ln(1). Do the same thing again and wheel about the ln(ln(1)). There's going to be complex solutions, Wolfram Alpah gets them but let me know if you figure out how to do it?
Answer:
x = 13/6
Step-by-step explanation:
We are the following expression;
x - 2(2 - (3/2)*x) = 2(4 - x) + 1
x - (4 - 3*x) = 8 - 2*x + 1
x - 4 + 3*x = 8 - 2*x + 1
4*x + 2*x = 9 + 4
6*x = 13
x = 13/6
Answer:
x = 4
Step-by-step explanation:
8/72 = x/36
crossmultiply
8 x 36 = X x 72
288 = 72x
divide both sides by 72
288/72 = x
therefore , x = 4
16x^2 + 25y^2 + 160x - 200y + 400 = 0 Rearrange and regroup.
(16x^2 + 160x) + (25y^2 - 200y ) = 0-400. Group the xs together and the ys together.
16(X^2 + 10x) + 25(y^2-8y) = -400. Factorising.
We are going to use completing the square method.
Coefficient of x in the first expression = 10.
Half of it = 1/2 * 10 = 5. (Note this value)
Square it = 5^2 = 25. (Note this value)
Coefficient of y in the second expression = -8.
Half of it = 1/2 * -8 = -4. (Note this value)
Square it = (-4)^2 = 16. (Note this value)
We are going to carry out a manipulation of completing the square with the values
25 and 16. By adding and substracting it.
16(X^2 + 10x) + 25(y^2-8y) = -400
16(X^2 + 10x + 25 -25) + 25(y^2-8y + 16 -16) = -400
Note that +25 - 25 = 0. +16 -16 = 0. So the equation is not altered.
16(X^2 + 10x + 25) -16(25) + 25(y^2-8y + 16) -25(16) = -400
16(X^2 + 10x + 25) + 25(y^2-8y + 16) = -400 +16(25) + 25(16) Transferring the terms -16(25) and -25(16)
to other side of equation. And 16*25 = 400
16(X^2 + 10x + 25) + 25(y^2-8y + 16) = 25(16)
16(X^2 + 10x + 25) + 25(y^2-8y + 16) = 400
We now complete the square by using the value when coefficient was halved.
16(x-5)^2 + 25(y-4)^2 = 400
Divide both sides of the equation by 400
(16(x-5)^2)/400 + (25(y-4)^2)/400 = 400/400 Note also that, 16*25 = 400.
((x-5)^2)/25 + ((y-4)^2)/16 = 1
((x-5)^2)/(5^2) + ((y-4)^2)/(4^2) = 1
Comparing to the general format of an ellipse.
((x-h)^2)/(a^2) + ((y-k)^2)/(b^2) = 1
Coordinates of the center = (h,k).
Comparing with above (x-5) = (x - h) , h = 5.
Comparing with above (y-k) = (y - k) , k = 4.
Therefore center = (h,k) = (5,4).
Sorry the answer came a little late. Cheers.
